Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

81.

A step-down transformer is used on a 2.2 kV line to deliver 110 V. How many turns are on the primary windings if the secondary has 25 turns?

A.

20

B.

250

C.

200

D.

500

Correct answer is D

Ep = 2.2kV = 2200V; Es=110V; Ns=25; Np=?

=\(\frac{E_p}{E_s}\) = \(\frac{N_p}{N_s}\)
 

= \(\frac{2200}{110}\) = \(\frac{N_p}{25}\)

=110 × Np = 2200 × 25

=\(N_p\) = \(\frac{55,000}{110}\)

∴\(N_p\) = 500 turns

82.

The pinhole camera works on

A.

the principle of the reversibility of light

B.

the principle of the rectilinear propagation of light

C.

Huygen’s principle

D.

the principle of total internal reflection of light

Correct answer is B

The pinhole camera works on the principle of the rectilinear propagation of light. This principle states that light travels in straight lines. When light passes through the tiny hole in a pinhole camera, it forms an inverted image on the opposite side of the camera. The size of the image depends on the distance between the object and the pinhole

83.

Which of the following is/are not true about the heat capacity of a substance?
(i) It is an intensive property
(ii) Its S.I unit is \(jK-1\)
(iii) It is an extensive property
(iv) Its S.I unit is \(jkg-1\)

A.

(i) and (iii) only

B.

(i), (ii) and (iv) only

C.

(i) and (iv) only

D.

(ii) and (iii) only

Correct answer is D

The S.I unit of heat capacity is JK-1 and it is an extensive property as it depends on the amount of substance present.

Therefore, (i) and (iv) only are not true

84.

The near point of a patient's eye is 50.0 cm. What power (in diopters) must a corrective lens have to enable the eye to see clearly an object 25.0 cm away?

A.

2 diopters

B.

2.5 diopters

C.

0.5 diopters

D.

3 diopters

Correct answer is A

The patient cannot see clearly an object closer than 50 cm

Therefore, the patient needs a lens that would enable him see clearly, objects placed 25 cm from the lens

So, we take the object to a distance of 25 cm from the lens so that the image forms at 50 cm in front of the lens

u=25cm ;v=-50cm (virtual image); p=

\(\frac{1}{f}\)=\(\frac{1}{u}\) + \(\frac{1}{v}\)

⇒\(\frac{1}{f}\) =\(\frac{1}{50}\)

⇒\(\frac{1}{f}\) = \(\frac{1}{25}\)-\(\frac{1}{50}\)

⇒\(\frac{1}{f}\) = f = 50cm =0.5m

⇒\(\frac{1}{f}\) = \(\frac{2-1}{50}\)

   p = \(\frac{1}{f}\)

   p =  \(\frac{1}{0.5}\)

   p =   2 diopters 
 
  ; The patient needs a converging lens with a power of 2 diopters

85.

A travelling wave of amplitude 0.80 m has a frequency of 16 Hz and a wave speed of 20 \(ms-1\)

Calculate the wave number of the wave.

A.

3

B.

42

C.

5

D.

2

Correct answer is C

A=0.8m; f=16Hz; v=20 \(ms^-1\); k=?

v = fλ

λ =1.25m


= k= \(\frac{2π}{λ}\) =\(\frac{2 × 3.142}{1.25}\)
 
 k=  5m ( to 1 s.f)