Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

726.

The instrument used to measure the pressure of a gas is

A.

barometer

B.

thermometer

C.

hydrometer

D.

manometer

Correct answer is D

Barometer is used to measure atmosphere pressure
Thermometer is used to measure temperature
Hydrometer is used to measure relative density of a liquid
Manometer is used to measure the pressure of a gas

727.

The net capacitance in the circuit above is

A.

80µF

B.

6.0µF

C.

4.0µF

D.

2.0µF

Correct answer is D

For capacitance i n parallel, 2µF and 2µF are in parallel,
their equivalence is 2µF and 2µF = 4µF

The 4µF generated is now in series with the remaining 4µF.

The net capacitance for series connection is

\(\frac{1}{C}\) = \(\frac{1}{4}\) + \(\frac{1}{4}\) = 1 + \(\frac{1}{4}\) = \(\frac{2}{4}\)

C = \(\frac{4}{2}\)

= 2µF

728.

Which of the following operations can be used to convert an alternative current dynamo into a direct current dynamo

A.

number of turns in the coil is increased

B.

strength of the field magnet is increased

C.

slip rings are replaced with split ring commutator

D.

coil is wound on a soft iron armature

Correct answer is C

A d.c generator is one in which its current is allowed to flow in one direction even through it may vary in value an a.c generator can only be made to produce a d.c by replacing the two slip rings with a single split ring or commutator

729.

When the r.m.s value of a source of electricity supply is given as 240v, it means that the peak value of the supply is

A.

240v

B.

340v

C.

480v

D.

57600v

Correct answer is B

The relationship between the peak value and r.m.s value of electricity supply is given as

V\(_{r.m.s}\) = \(\frac{V_o}{\sqrt{2}}\)

where Vo = peak voltage

∴ Vo = V\(_{r.m.s}\) × √2

= 240 × √2

= 339.5v

= 340v

730.

When two objects P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of Q. The mass of P is half that of Q. The ratio of the specific heat capacity pf P to Q is

A.

1:4

B.

4:1

C.

1:1

D.

2:1

Correct answer is C

H = mcθ

HP = HQ, θP = 2θ,

mP = \(\frac{1}{2}\)mQ

∴ HP = mQCPθP, also HQ = mQCQθQ

Since HP = HQ

∴ mPcPθP = mQcPθq

Putting in the conditions

\(\frac{1}{2}\)mQ × cP × 2θQ = mQ × θQ × cQ

∴ cP = cQ

\(\frac{C_p}{C_Q}\)= \(\frac{1}{1}\)

= 1:1