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Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

721.

How can energy loss be minimized through Eddy-current?

A.

By using high resistance wire

B.

By using insulated soft iron wires

C.

By using low resistance wires

D.

By using turns of wires

Correct answer is A

Eddy currents are produced by the varying flux cathode, the iron core of an equipment thus reducing efficiency due to power consumption. It can be reduced by laminating the core by breaking up the path of eddy current or by increasing the resistance of the core
Usage of insulated soft iron wire is to reduce hysteresis loss
Usage of low resistance wire (thick wire) is to reduce I2R loss
Usage of thick wire is to reduce leakage heat loss due to leakage of magnetic flux
Thus the correct answer is to use high resistance wire or thin wire

722.

A string of length 5cm is extended by 0.04m when a load of 0.8kg is suspended at the end. How far will it extend if a force of 16N is applied? [g = 10ms2]

A.

0.04m

B.

0.12m

C.

0.01m

D.

0.08m

Correct answer is D

From Hoke's Law, F = ke, K = Constant of Force

For he first case, Force = mg,

= 0.8 × 10 = 8N

∴ 8 = k × 0.04

k = 80.04

= 200Nm

Since K is constant

For the second case, F = ke

F = 200 × e

∴ e = F200

= 16200

= 0.08m

723.

Determine the focal length of a thin converging lens if the power is 5.0 dioptres

A.

0.1 m

B.

0.2 m

C.

2.0 m

D.

2.5 m

Correct answer is B

Power of a lens = 1f

f = focal length

f = 1p

= 15

= 0.2m

724.

A radio station broadcast at a frequency of 600KHZ. If the speed of light in air is 3 × 108ms1. Calculate the wavelength of the radio wave

A.

2.20 × 103m

B.

5.0 × 102m

C.

5.0 × 105m

D.

11.8 × 1011m

Correct answer is B

V = fλ

λ = vf

= 3×108600×103 = 500m

= 5 × 102m

N.B 600KHz Frequency = 600 × 103Hz

725.

A man of mass 50kg ascends a flight of stains 5m high in 5 seconds. If acceleration due to gravity is 10ms2 the power expended is

A.

100w

B.

200w

C.

400w

D.

500w

Correct answer is D

Power is the time rate of doing work

i.e power = energytime

Since energy = mgH

∴ power = mgHt

= 50×10×5t

= 500W