The net capacitance in the circuit above is
...
The net capacitance in the circuit above is
80µF
6.0µF
4.0µF
2.0µF
Correct answer is D
For capacitance i n parallel, 2µF and 2µF are in parallel,
their equivalence is 2µF and 2µF = 4µF
The 4µF generated is now in series with the remaining 4µF.
The net capacitance for series connection is
1C = 14 + 14 = 1 + 14 = 24
C = 42
= 2µF
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