How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Evaluate \(\frac{2\log_{3} 9 \times \log_{3} 81^{-2}}{\log_{5} 625}\)
4
-32
-8
16
Correct answer is C
\(\frac{2\log_{3} 9 \times \log_{3} 81^{-2}}{\log_{5} 625}\)
= \(\frac{2\log_3 3^2 \times \log_3 (3^4)^{-2}}{\log_5 (5^4)}\)
= \(\frac{4\log_3 3 \times -8\log_3 3}{4\log_5 5}\)
= -8.
Find the value of k in the equation: \(\sqrt{28} + \sqrt{112} - \sqrt{k} = \sqrt{175}\)
\(\sqrt{28}\)
7
28
\(\sqrt{7}\)
Correct answer is B
\(\sqrt{28} + \sqrt{112} - \sqrt{k} = \sqrt{175}\)
\(\sqrt{4 \times 7} + \sqrt{16 \times 7} - \sqrt{k} = \sqrt{25 \times 7}\)
\(2\sqrt{7} + 4\sqrt{7} - \sqrt{k} = 5\sqrt{7}\)
\(6\sqrt{7} - 5\sqrt{7} = \sqrt{k}\)
\(\sqrt{k} = \sqrt{7}\)
\(\implies k = 7\)
144 ways
15 ways
185 ways
12 ways
Correct answer is D
For the committee to include 2 females, we must have 3 males, so that there should be 5 members.
That is, \(^4C_3 \times ^3C_2\)
= \(\frac{4!}{(4 - 3)! 3!} \times \frac{3!}{(3 - 2)! 2!}\)
= 4 × 3 = 12 ways
{1, 3, 6}
{3, 5, 9, 12}
{3, 9, 15}
{2, 3, 9}
Correct answer is C
μ = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20} A = {3, 6, 9, 12, 15, 18} B = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19} A ∩ B = {3, 9, 15}
If the 3rd and 7th terms of a G.P are 9 and 1/9 respectively. Find the common ratio.
\(\frac{1}{3}\)
\(\frac{1}{9}\)
\(\frac{2}{3}\)
\(\frac{2}{9}\)
Correct answer is A
\(T_n = ar^{n - 1}\) (terms of a G.P)
\(T_3 = ar^2 = 9\) ... (i)
\(T_7 = ar^6 = \frac{1}{9}\) ... (ii)
Divide (i) by (ii);
\(\frac{ar^6}{ar^2} = \frac{\frac{1}{9}}{9}\)
\(r^4 = \frac{1}{81}\)
\(r^4 = (\frac{1}{3})^4\)
\(r = \frac{1}{3}\)