How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
\(\frac{15}{17}\)
\(\frac{8}{17}\)
\(\frac{8}{15}\)
\(\frac{12}{17}\)
Correct answer is A
ABCD is the floor. By pathagoras
AC\(^2\) = 144 + 81 = \(\sqrt{225}\)
AC = 15cm
Height of room 8m, diagonal of floor is 15m
Therefore, the cosine of the angle which a diagonal of the room makes with the floor is
EC\(^2\) = 15\(^2\) + 8\(^2\) cosine
\(\frac{adj}{Hyp} = \frac{15}{17}\)
EC\(^2\) = \(\sqrt{225 + 64}\)
EC = \(\sqrt{289}\)
= 17
What is the circumference of latitude 0\(^o\)S if R is the radius of the earth?
cos \(\theta\)
2\(\pi\)R cos \(\theta\)
R sin \(\theta\)
2 \(\pi\) r sin \(\theta\)
Correct answer is B
Circumstances of latitude 0\(^o\)s where R is the radius of the earth 2\(\pi\)r cos \(\theta\)
180
60
25
20
Correct answer is D
Let x rep. numbers of boys that can work at \(\frac{5}{4}\) the rate at
which the 10 girls work
For 1 hrs, x boys will work for \(\frac{\frac{1}{5} \times 10}{4}\)
x = \(\frac{5}{4}\) x 10
= 8 boys
8 boys will do the work of ten girls at the same rate
4 + 8 = 12 bous cut the field in 5 hrs for 3 hrs,
\(\frac{12 \times 5}{3}\) boys will be needed = 20 boys.
0
0.9
1.1
1.2
Correct answer is C
\(\frac{0.021741 \times 1.2047}{0.023789}\) = \(\frac{0.0255 \times 1.2}{0.024}\) (to 216)
= \(\frac{0.0264}{0.024}\) = 1.1
x < 11
x < -1
x > 6
x > 11
Correct answer is D
\(\frac{1}{3}\) (x + 1) - 1 > \(\frac{1}{5}\)(x + 4) = \(\frac{x + 1}{3} - 1\) > \(\frac{x + 4}{5}\)
\(\frac{x + 1}{3} - \frac{x + 4}{5} -1\) > 0
= \(\frac{5x + 5 - 3x - 12}{15}\)
2x - 7 > 15
2x > 22 = x > 11