How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
12cm
10cm
8cm
6cm
Correct answer is D
p from LM = \(\sqrt{10^2 - 8^2}\)
= \(\sqrt{36}\) = 6cm
x - y = 1
x + y = 1
x + y = 5
x - y = 5
Correct answer is C
m = tan 135° = -tan 45° = -1
\(\frac{y - y_1}{x - x_1}\) = m
\(\frac{y - 3}{x - 2}\) = -1
= y - 3 = -(x - 2)
= -x + 2
x + y = 5
A cone with the sector angle of 45° is cut out of a circle of radius r of the cone.
\(\frac{r}{16}\) cm
\(\frac{r}{6}\) cm
\(\frac{r}{8}\) cm
\(\frac{r}{2}\) cm
Correct answer is C
The formula for the base radius of a cone formed from the sector of a circle = \(\frac{r \theta}{360°}\)
= \(\frac{r \times 45°}{360°}\)
= \(\frac{r}{8} cm\)
22cm2
44cm2
66cm2
88cm2
Correct answer is A
Area of a sector = \(\frac{\theta}{360°} \times \pi r^{2}\)
r = 6cm; \(\theta\) = 70°.
Area of the sector = \(\frac{70}{360} \times \frac{22}{7} \times 6^{2}\)
= \(22 cm^{2}\)
22cm
44cm
110cm
220cm
Correct answer is A
Diameter = 42cm
Length of the arc = \(\frac{\theta}{360°} \times \pi d\)
= \(\frac{60}{360} \times \frac{22}{7} \times 42cm\)
= \(22cm\)