How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
tan x cosec x
-cot x cosec x
tan x sec x
-cot x sec x
Correct answer is B
\(\csc x = \frac{1}{\sin x}\)
Using the quotient rule,
\(\frac{\mathrm d y}{\mathrm d x} = \frac{vdu - udv}{v^{2}}\)
= \(\frac{\sin x (0) - 1 (\cos x)}{(\sin x)^{2}}\)
= \(\frac{- \cos x}{\sin^{2} x}\)
= \((\frac{- \cos x}{\sin x}) (\frac{1}{\sin x})\)
= \(- \cot x \csc x\)
60m
30 \(\sqrt{3}\)m
20 \(\sqrt{3}\)m
10 \(\sqrt{3}\)m
Correct answer is B
h = 30 tan 60°
= 30\(\sqrt{3}\)
100o
80 o
50 o
40 o
Correct answer is B
< PYU = < YPQ = 40°(Alternative) = PQ\(\parallel\)UV
< XPQ = < YPQ = 40°, Since QX = QY
therefore < XPY = 80°
x + 2y - 1= -0
2x + y - 3 = 0
x - 2y - 3 = 0
2x + y - 1 = 0
Correct answer is D
Line PQ : x - 2y + 4 = 0
2y = x + 4 \(\implies y = \frac{x}{2} + 2 \)
Slope = \(\frac{1}{2}\)
Slope of the perpendicular line QR: \(\frac{-1}{\frac{1}{2}} = -2\)
Line QR: \(y = mx + b\)
\(y = -2x + b\)
Point of intersection: (1, -1)
\(-1 = -2(1) + b \implies b = -1 + 2 = 1\)
\(y = -2x + 1 \implies y + 2x - 1 = 0\)
\(QR: 2x + y - 1 = 0\)
\(\frac{1100}{3}\)km
\(\frac{2200}{3}\)km
\(\frac{22000}{3}\)km
\(\frac{1100}{3}\)km
Correct answer is C
Angular difference = 45° + 15° = 60°.
\(D = \frac{60°}{360°} \times 2 \times \frac{22}{7} \times 7000\)
= \(\frac{22000}{3} km\)