How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Solve the following equation equation for \(x^2 + \frac{2x}{r^2} + \frac{1}{r^4}\) = 0
r2
\(\frac{1}{r^4}\)
-\(\frac{1}{r^2}\)
1 - r
Correct answer is C
\(x^2 + \frac{2x}{r^2}\) + \(\frac{1}{r^4}\) = 0
(x + \(\frac{1}{r^2}\)) = 0
x + \(\frac{1}{r^2}\) = 0
x = \(\frac{-1}{r^2}\)
Simplify \(\frac{x + 2}{x + 1}\) - \(\frac{x - 2}{x + 2}\)
\(\frac{3}{x + 1}\)
\(\frac{3x + 2}{(x + 1)(x + 2)}\)
\(\frac{5x + 6}{(x + 1)(x + 2)}\)
\(\frac{2x^2 + 5x + 2}{(x + 1)(x + 2)}\)
Correct answer is C
\(\frac{x + 2}{x + 1}\) - \(\frac{x - 2}{x + 2}\) = \(\frac{(x + 2)(x + 2) - (x -2) - (x - 2)(x + 1)}{(x + 1)(x + 2)}\)
= \(\frac{(x^2 + 4x + 4) - (x^2 - x - 2)}{(x + 1)(x + 2)}\) = \(\frac{x^2 + 4x + 4 - x^2 + x + 2}{(x + 1)(x + 2)}\)
= \(\frac{5x + 6}{(x + 1)(x + 2)}\)
2.25 x 10-4m
50 x 10-4m
2.25 x 10-5m
4.50 x 10-5m
Correct answer is D
Thickness of an 800 pages book = 18mm to meter
18 x 103m = 1.8 x 10-2m
One leaf = \(\frac{1.8 \times 10^{-2}}{800}\)
= \(\frac{1.8 \times 10^{-2}}{8 \times 10^{2}}\)
= \(\frac{-1.8}{8}\) x 10-4
= 0.225 x 10-4
= 2.25 x 10-5m
one leaf contains 2 pages
: 2 * 2.25 x 10\(^{-5}\)m
= 4.5 * 10\(^{-5}\)m
Find m such that (m + \(\sqrt{3}\))(1 - \(\sqrt{3}\))2 = 6 - 2\(\sqrt{2}\)
1
2
3
4
Correct answer is C
(m + \(\sqrt{3}\))(1 - \(\sqrt{3}\))2 = 6 - 2\(\sqrt{2}\)
(m + \(\sqrt{3}\))(4 - 2\(\sqrt{3}\)) = 6 - 2\(\sqrt{2}\)
= 6 - 2\(\sqrt{3}\)
4m - 6 + 4 - 2m\(\sqrt{3}\) = 6 - 2\(\sqrt{3}\)
comparing co-efficients,
4m - 6 = 6.......(i)
4 - 2m = -2.......(ii)
in both equations, m = 3
0.3010
0.4771
0.6532
0.9542
Correct answer is C
If \(log_{10} 2 = 0.3010\) and \(log_{10} 3 = 0.4771\),
\(\log_{10} 4.5 = \log_{10} (\frac{3 \times 3}{2})\)
\(log_{10} 3 + log_{10} 3 - log_{10} 2 = 0.4771 + 0.4771 - 0.3010\)
= 0.6532