0.3010
0.4771
0.6532
0.9542
Correct answer is C
If \(log_{10} 2 = 0.3010\) and \(log_{10} 3 = 0.4771\),
\(\log_{10} 4.5 = \log_{10} (\frac{3 \times 3}{2})\) \(log_{10} 3 + log_{10} 3 - log_{10} 2 = 0.4771 + 0.4771 - 0.3010\) = 0.6532
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