How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Simplify \(\frac{0.0324 \times 0.00064}{0.48 \times 0.012}\)
3.6 x 102
3.6 x 10-2
3.6 x 10-3
3.6 x 10-4
Correct answer is C
\(\frac{0.0324 \times 0.00064}{0.48 \times 0.012}\) = \(\frac{324 \times 10^{-4} \times 10^{-5}}{48 x 10^{-2} x 12 x 10^{-3}}\)
\(\frac{324 \times 64 \times 1 0^{-9}}{48 \times 12 \times 10^{-5}}\) = 36 x 10-4
= 3.6 x 10-3
If P = 18, Q = 21, R = -6 and S = -4, Calculate \(\frac{(P- Q)^3 + S^2}{R^3}\)
\(\frac{-11}{216}\)
\(\frac{11}{216}\)
\(\frac{-43}{116}\)
\(\frac{43}{116}\)
Correct answer is B
\(\frac{(P- Q)^3 + S^2}{R^3}\) = \(\frac{(18 - 21)^3 + (-4)^2}{(-6)^3}\)
= \(\frac{-27 + 16}{R^3}\)
= \(\frac{-11}{-216}\)
= \(\frac{11}{216}\)
60
54
48
42
Correct answer is B
let x represent the total number of oranges shared, let the three boys be A, B and C respectively. A received \(\frac{1}{3}\) of x, Remainder = \(\frac{2}{3}\) of x . B received \(\frac{2}{3}\) of remainder (i.e.) \(\frac{2}{3}\) of x
∴ C received \(\frac{2}{3}\) of remainder (\(\frac{2}{3}\) of x) = 12
\(\frac{1}{3}\) x \(\frac{2x}{3}\) = 12
2x = 108
x = 54
Find the reciprocal of \(\frac{\frac{2}{3}}{\frac{1}{2} + \frac{1}{3}}\)
\(\frac{4}{5}\)
\(\frac{5}{4}\)
\(\frac{2}{5}\)
\(\frac{6}{7}\)
Correct answer is B
\(\frac{2}{3}\) = \(\frac{2}{3}\)
= \(\frac{2}{3}\) x \(\frac{6}{5}\)
= \(\frac{4}{5}\)
reciprocal of \(\frac{4}{5}\) = \(\frac{1}{\frac{4}{5}}\)
= \(\frac{5}{4}\)
Find the smallest number by which 252 can be multiplied to obtain a perfect square
2
3
5
7
Correct answer is D
\(252 = 2^{2} \times 3^{2} \times 7\)
\(\therefore\) To make 252 a perfect square, the smalest number to multiply with = 7.
\(252 \times 7 = 1764 = 42^{2}\)