How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
-1 < x < 0 and 0 < x < 1
-2 < x < -1 and 0 < x < 1
-2 < x < -1 and -1 < x < 0
0 < x < 1
Correct answer is B
If the graph of y = x3 - 3x + 1 is plotted,the graph crosses the x-axis in the ranges -2 < x < -1 and 0 < x < 1
(5, 6)
(8, 8)
(8, 5)
(7,7)
(7, 5)
Correct answer is E
When y = 5, y = x2 - 12x + 40, becomes
x2 - 12x + 40 = 5
x2 - 12x + 40 - 5 = 0
x2 + 12x + 35 = 0
x2 - 7x - 5x + 35 = 0
x(x - 7) - 5(x - 7) = 0
= (x - 5)(x - 7)
x = 5 or 7
2(x + 3)(3x - 2)
6(x - 2)(x + 1)
2(x - 3)(3x + 2)
6(x + 2)(x - 1)
(3x - 4)(2x + 3)
Correct answer is C
6x2 - 14x - 12 = 6x2 - 18x + 4x - 12
(3x + 2)(2x - 6)
= 3x(2x - 6) + 2(2x - 6)
= (3x + 2) 2(x - 3)
72
100
90
200
125
Correct answer is D
P \(\alpha\) \(\frac{q^2}{r}\)
P = \(\frac{kq^2}{r}\)
k = \(\frac{pr}{q^2}\)
= \(\frac{36 x 4}{(3)^2}\)
p = \(\frac{16q^2}{r}\)
= \(\frac{16 \times 25}{2}\)
= 200
Simplify \(\frac{3^n - 3^{n - 1}}{3^3 \times 3^n - 27 \times 3^{n - 1}}\)
1
6
\(\frac{1}{27}\)
\(\frac{4}{3}\)
Correct answer is C
\(\frac{3^n - 3^{n - 1}}{3^3 \times 3^n - 27 \times 3^{n - 1}}\) = \(\frac{3^n - 3^{n - 1}}{3^3(3^n - 3^{n - 1})}\)
= \(\frac{3^n - 3^{n - 1}}{27(3^n - 3^{n - 1})}\)
= \(\frac{1}{27}\)