How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Find x if (x\(_4\))\(^2\) = 100100\(_2\)
6
12
100
210
110
Correct answer is B
x\(_4\) = x \(\times\) 4\(^0\) = x in base 10.
100100\(_2\) = 1 x 2\(^5\) + 1 x 2\(^2\)
= 32 + 4
= 36 in base 10
\(\implies\) x\(^2\) = 36
x = 6 in base 10.
Convert 6 to a number in base 4.
| 4 | 6 |
| 4 | 1 r 2 |
| 0 r 1 |
= 12\(_4\)
47
50
48\(\frac{1}{2}\)
48
49
Correct answer is C
By re-arranging 21, 23, 29, 40, 41, 43| 47, 50| 50, 55, 56, 70, 70, 73
The median = \(\frac{47 + 50}{2}\)
\(\frac{97}{2}\)
= 48\(\frac{1}{2}\)
The lengths of the sides of a right angled triangle are (3x + 1)cm, (3x - 1)cm and xcm. Find x
2
6
18
12
5
Correct answer is D
\((3x + 1)^{2} = (3x - 1)^{2} + x^{2}\) (Pythagoras's theorem)
\(9x^{2} + 6x + 1 = 9x^{2} - 6x + 1 + x^{2}\)
x2 - 12x = 0
x(x - 12) = 0
x = 0 or 12
The sides cannot be 0 hence x = 12.
Simplify \(\frac{x - 7}{x^2 - 9}\) x \(\frac{x^2 - 3x}{x^2 - 49}\)
\(\frac{x}{(x - 3)(x - 7)}\)
\(\frac{x}{(x + 3)(x - 7)}\)
\(\frac{x}{(x + 3)(x + 7)}\)
\(\frac{x}{(x - 3)(x + 7)}\)
Correct answer is C
\(\frac{x - 7}{x^2 - 9}\) x \(\frac{x^2 - 3x}{x^2 - 49}\)
= \(\frac{x - 7}{(x - 3)(x + 3)}\) x \(\frac{x(x - 3)}{(x - 7)(x + 7)}\)
= \(\frac{x}{(x + 3)(x + 7)}\)
y = \(\frac{10x^2}{31} + \frac{52}{31\sqrt{x}}\)
y = x2 + \(\frac{1}{\sqrt{x}}\)
y = x2 + \(\frac{1}{x}\)
y = \(\frac{x^2}{31} + \frac{1}{31\sqrt{x}}\)
Correct answer is A
y = kx2 + \(\frac{c}{\sqrt{x}}\)
y = 2when x = 1
2 = k + \(\frac{c}{1}\)
k + c = 2
y = 6 when x = 4
6 = 16k + \(\frac{c}{2}\)
12 = 32k + c
k + c = 2
32k + c = 12
= 31k + 10
k = \(\frac{10}{31}\)
c = 2 - \(\frac{10}{31}\)
= \(\frac{62 - 10}{31}\)
= \(\frac{52}{31}\)
y = \(\frac{10x^2}{31} + \frac{52}{31\sqrt{x}}\)