How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
3y - x = 0; 2y - x = 0
3y - x = 14; x - 2y = 6
3y - x =7; x - 2y = 6
3y - x = 14; y - 2x = 6
x + 3y = 7; x = 2y = 12
Correct answer is B
7 years ago, Father(x - 7) years old, Son (y - 7) years x - 7 = 3(y - 7) x - 7 = 3y - 21 3y - x = -7 + 21 = 14 3y - x = 14 ... (1) In six years time, x + 6 = 2(y + 6) x + 6 = 2y + 12 2y + 12 = x + 6 12 - 6 = x - 2y 6 = x - 2y ... (2)
If N560.70 is shared in the ratio 7 : 2 : 1, what is the smallest share?
N392.49
N56.70
N113.40
N112.14
N56.07
Correct answer is E
7 + 2 + 1 = 10
\(\frac{1}{10}\) x 560.70
= N56.07
Simplify 3 - 2 \(\div\) \(\frac{4}{5}\) + \(\frac{1}{2}\)
1\(\frac{3}{4}\)
-1
1\(\frac{3}{10}\)
1
1\(\frac{9}{10}\)
Correct answer is D
3 - 2 \(\div\) (\(\frac{4}{5}\)) + \(\frac{1}{2}\)
3 - (2 x \(\frac{5}{4}\)) + \(\frac{1}{2}\) = 3 - \(\frac{10}{4}\) + \(\frac{1}{2}\)
= 3 - \(\frac{5}{2}\) + \(\frac{1}{2}\)
= \(\frac{6 - 5 + 1}{2}\)
= \(\frac{2}{2}\)
= 1
Rationalize the expression \(\frac{1}{\sqrt{2} + \sqrt{5}}\)
\(\frac{1}{3}\)(\(\sqrt{5} - \sqrt{2}\)
\(\frac{\sqrt{2}}{3}\) + \(\frac{\sqrt{5}}{5}\)
\(\sqrt{2} - \sqrt{5}\)
5(\(\sqrt{2} - \sqrt{5}\)
\(\frac{1}{3}\)(\(\sqrt{2} - \sqrt{5}\)
Correct answer is A
\(\frac{1}{\sqrt{2} + \sqrt{5}}\)
\(\frac{1}{\sqrt{2} + \sqrt{5}} \times \frac{(\sqrt{2} - \sqrt{5})}{(\sqrt{2} - \sqrt{5})}\)
= \(\frac{\sqrt{2} - \sqrt{5}}{2 - 5}\)
= \(\frac{\sqrt{2} - \sqrt{5}}{-3}\)
= \(\frac{1}{3} (\sqrt{5} - \sqrt{2})\)
120km/hr
60km/hr
670km/hr
40km/hr
Correct answer is B
Speed = \(\frac{distance}{time}\)
let x represent the speed, d represent distance
x = \(\frac{d}{4}\)
d = 4x
2x = \(\frac{600 - d}{3}\)
6x = 600 - d
6x = 600 - 4x
10x = 600
x = \(\frac{600}{10}\)
= 60km/hr