How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
2
4
\(\sqrt{10}\)
35
2.2
Correct answer is C
a = 2i - 3j - 3i + 6j
= -i + 3j
= \(\sqrt{5 \times 2}\)
= \(\sqrt{10}\)
3 + \(\sqrt{3}\)
5 + \(\sqrt{3}\)
3 - \(\sqrt{3}\)
1
\(\sqrt{3}\) - 1
Correct answer is D
No explanation has been provided for this answer.
Evaluate without using tables sin(-1290º)
\(\frac{3}{2}\)
-\(\frac{3}{2}\)
\(\frac{2}{2}\)
1
\(\frac{1}{2}\)
Correct answer is E
sin(-1290º) = -sin(1290º)
sin([3*360] + 210)
where sin 360 = 0 and sin 210 = 180 + 30 ⇔ -30º
-sin ([3* 0] + [-30])
-sin(-30)
sin30 = \(\frac{1}{2}\)
k = -7, 1 = -15
k = -15, 1 = -7
k = \(\frac{15}{3}\) , 1 = -7
k = \(\frac{7}{3}\) , 1 = -17
Correct answer is A
If k = -7 is put as -15, the equation x4 - kx3 + 10x2 + 1x - 3 becomes x4 - (7x3) + 10x2 + (15)-3 = x4 + 7x3 + 10x2 - 15x - 3
This equation is divisible by (x - 1) and (x + 2) with the remainder as 27
k = -7, 1 = -15
Simplify \(\frac{(a^2 - \frac{1}{a}) (a^{\frac{4}{3}} + a^{\frac{2}{3}})}{a^2 - \frac{1}{a}^2}\)
a\(\frac{2}{3}\)
a-\(\frac{1}{3}\)
\(a^{2}\) + 1
a
a\(\frac{1}{3}\)
Correct answer is E
\(\frac{(a^2 - \frac{1}{a})(a^{\frac{4}{3}} + a^{\frac{2}{3}})}{a^2 - \frac{1}{a}^2}\)
= \(\frac{(\frac{a^2 - 1}{a})(\frac{a^2 + 1}{a^{\frac{2}{3}}})}{a^{4} - \frac{1}{a^2}}\)
= \(\frac{a^4 - 1}{a^{\frac{5}{3}}}\) x \(\frac{a^2}{a^4 - 1}\)
= a\(\frac{1}{3}\)