How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
43.36cm2
32.072
18.212
6.932
Correct answer is C
Area of shaded portion = Area of semicircle
Area of \(\bigtriangleup\) RSO
Area of semicircle = \(\frac {\pi r^2}{2} = \frac{22\times 4 \times 4}{7 \times 2}\)
= 25.14cm2; Area of \(\bigtriangleup\)RSO
=\(\sqrt{s(s - 1)(s - b)(s - c)}\); where
s = \(\frac{a + b + c}{2}\)
s = \(\frac{4 + 4 + 4}{2}\)
= 6cm
= \(\sqrt{6(6 - 4)(6 - 4) (6 - 4)}\)
= \(\sqrt{6(2) (2) (2)}\)
= \(\sqrt{18}\) = 6.93cm2
Area of shaded region
= 25.14 - 6.93
= 18.21cm2
In the diagram, |XR| = 4cm
|RZ| = 12cm, |SR| = n, |XZ| = m and SR||YZ. Find m in terms of n
m = 2n
m = 3n
m = 4n
m = 5n
Correct answer is C
\(\frac{n}{4} = \frac{m}{4 + 12}\)
\(\frac{n}{4} = \frac{m}{16}\)
4m = 16n
\(\frac{4m}{4} = \frac{16n}{4}\)
m = 4n
In the diagram, O is the centre of the circle and < PQR = 106º, find the value of y
16
37
74
127
Correct answer is C
2y + Reflex angle = 360
Reflex angle = 360 - 2y
360 - 2y = 2(106)(angles at a centre = 2ce < of circum.)
360 - 212 = 2y
148 = 2y
y \(\frac{148}{2}\)
y = 74o
If the ratio x:y = 3:5 and y:z = 4:7, find the ratio x:y:z
15 : 28 : 84
12 : 20 : 35
3 : 5 : 4
5 : 4 : 7
Correct answer is B
x : y = 3.5, y : z = 4 : 7
x = 3 x 4 = 12
y = 5 x 4 = 20
y = 4 x 5 = 20
z = 7 x 5 = 35
then x : y : z = 12 : 20 : 35
10
12
15
17
Correct answer is D
at least 2 kinds of food two or more foods i.e(R and p) + (p and Y) + (y and R) + R and y and p = 6 + 2 + 4 + 5 = 17