How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Factorize completely: 6ax - 12by - 9ay + 8bx
(2a - 3b)(4x + 3y)
(3a + 4b)(2x - 3y)
(3a - 4b)(2x + 3y)
(2a + 3b)(4x -3y)
Correct answer is B
6ax - 12by - 9ay + 8bx
= 6ax - 9ay + 8bx - 12by
= 3a(2x - 3y) + 4b(2x - 3y)
= (3a + 4b)(2x - 3y)
If 2n = y, Find 2\(^{(2 + \frac{n}{3})}\)
4y\(^\frac{1}{3}\)
4y\(^-3\)
2y\(^\frac{1}{3}\)
2y\(^-3\)
Correct answer is A
If 2n = y,
then, 2\(^{(2 + \frac{n}{3})}\) = 22 x 2\(^\frac{n}{3}\)
= 4 x (2n)\(^{\frac{1}{3}}\)
But y = 2n, hence
2\(^{(2 + \frac{n}{3})}\) = 4 x y\(^{\frac{1}{3}}\)
= 4y\(^\frac{1}{3}\)
Given that logx 64 = 3, evaluate x log\(_2\)8
6
9
12
24
Correct answer is C
If logx 64 = 3, then \(64 = x^3\)
\(4^3 = x^3\)
Since the indices are equal,
x = 4
Hence, x log\(_2\)8
= 4(3.log\(_2\)2)
= where log\(_2\)2 = 1(1)
= 12 X 1
= 12
Find the 7th term of the sequence: 2, 5, 10, 17, 6,...
37
48
50
63
Correct answer is C
No explanation has been provided for this answer.
If \(\frac{27^x \times 3^{1 - x}}{9^{2x}} = 1\), find the value of x.
1
\(\frac{1}{2}\)
-1
Correct answer is B
\(\frac{27^x \times 3^{1 - x}}{9^{2x}} = 1\)
\(\frac{3^{3x} \times 3^{1 - x}}{3^{2(2 - x)}} = 3^0\)
\(3^{3x} \times 3^{1 - x} \div 3^{4x} = 3^0\)
\(3^{(3x + 1 - x - 4x)} = 3^0\)
\(3^{(1 - 2x)} = 3^0\)
since the bases are equal,
1 - 2x = 0
- 2x = -1
x = \(\frac{1}{2}\)