How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
22o
45o
67o
89o
Correct answer is B
In In the diagram given, \(\alpha\) = 22o (vertically opp. angles), \(\alpha\) = \(\beta\) (alternate angles)
< PSQ + 133o + \(\beta\) = 180o (sum of angles of a \(\Delta\))
< PSQ + 133o + 22o = 180o
< PSQ = 180o - (133 + 22)o
45o
70o
80o
105o
110o
Correct answer is B
In the diagram above, x1 = 50(angles in alternate segment)
x1 = x2(base angles of isos. \(\Delta\))
< UXY + x2 + 50o = 180o(sum of angles on a straight line)
< UXY + 50o + 50o = 180p
< UXY + 100o = 180o
< UXY = 180o - 100o
= 80o
13
14
15
16
Correct answer is B
Median = \(\frac{N}{2}\)th age
= \(\frac{50}{2}\)th age
= 25th age
= 14 years
50
55
60
65
Correct answer is A
Number of students in the club is
10 + 24 + 8 + 5 + 3 = 50
32o
40o
60o
69o
Correct answer is D
sin 60o = x + 0.5 0o(given)
0.8660 = x + 0.5
0.8660 - 0.5 = x
x = 0.3660
cos\(\theta\) = x(given)
cos\(\theta\) = 0.3660
Hence, \(\theta\) = cos-1(0.3660)
= 68.53o
= 69o (nearest degree)