22o
45o
67o
89o
Correct answer is B
In In the diagram given, \(\alpha\) = 22o (vertically opp. angles), \(\alpha\) = \(\beta\) (alternate angles)
< PSQ + 133o + \(\beta\) = 180o (sum of angles of a \(\Delta\))
< PSQ + 133o + 22o = 180o
< PSQ = 180o - (133 + 22)o
45o