How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
16
14
12
10
Correct answer is A
Range = Highest Number - Lowest Number
Mode is the number with highest occurrence
10, 9, 10, 9, 8, 7, 7, 10, 8, 4, 6,, 9, 10, 9, 7, 10, 6, 5
Range = 10 − 4 = 6
Mode = 10
Sum of range and mode = range + mode = 6 + 10
= 16
100o
140o
120o
10o
Correct answer is C
If RST = 60o
RXT = 2 × RST
(angle at the centre twice angle at the circumference)
RXT = 2 × 60
= 120o
The locus of a point which is equidistant from the line PQ forms a
circle centre P
pair of parallel lines each opposite to PQ
circle centre Q
perpendicular line to PQ
Correct answer is D
The locus of points at a fixed distance from the point P is a circle with the given P at its centre.
The locus of points at a fixed distance from the point Q is a circle with the given point Q at its centre
The locus of points equidistant from two points P and Q i.e line PQ is the perpendicular bisector of the segment determined by the points
Hence, The locus of a point which is equidistant from the line PQ forms a perpendicular line to PQ
Simplify 3 \(^{n − 1}\) × \(\frac{27^{n + 1}}{81^n}\)
3\(^{2n}\)
9
3n
3 \(^{n + 1}\)
Correct answer is B
3\(^{n - 1}\) × \(\frac{27^{n + 1}}{81^n}\)
= 3\(^{n - 1}\) × \(\frac{3^{3(n + 1)}}{3^{4n}}\)
= 3\(^{n - 1 + 3n + 3 − 4n}\)
= 3\(^{4n − 4n − 1 + 3}\)
= \(3^{2}\)
= 9
Given m = N\(\sqrt{\frac{SL}{T}}\) make T the subject of the formula
\(\frac{\text{NSL}}{M}\)
\(\frac{N^2SL}{M^2}\)
\(\frac{N^2SL}{M}\)
\(\frac{NSL}{M^2}\)
Correct answer is B
M = N \(\sqrt{\frac{SL}{T}}\),
make T subject of formula square both sides
M\(^{2}\) = \(\frac{N^2SL}{T}\)
TM\(^{2}\) = N\(^{2}\)SL
T = \(\frac{N^2SL}{M^2}\)