3\(^{2n}\)
9
3n
3 \(^{n + 1}\)
Correct answer is B
3\(^{n - 1}\) × \(\frac{27^{n + 1}}{81^n}\) = 3\(^{n - 1}\) × \(\frac{3^{3(n + 1)}}{3^{4n}}\) = 3\(^{n - 1 + 3n + 3 − 4n}\) = 3\(^{4n − 4n − 1 + 3}\) = \(3^{2}\) = 9
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