How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
₦ 35, 000
₦ 40,000
₦ 25,000
₦ 20,000
Correct answer is D
Total angle at a point = 3600
∴ To get the angle occupied by fertilizer we have,
40 + 50 + 80 + 70 + 30 + fertilizer(x) = 360
270 + x = 360
x = 360 - 270
x = 90
Total amount allocated to the farm
= ₦ 80,000
∴Amount allocated to the fertilizer
= \(\frac{\text{fertilizer (angle) × Total amount}}{\text{total angle}}\)
= \(\frac{90}{360}\) × 80,000
= ₦20,000
Find the principal which amounts to ₦ 5,500 at a simple interest in 5 years at 2% per annum
₦ 4,900
₦ 5,000
₦ 4,700
₦ 4,000
Correct answer is B
Principal = P, Simple Interest = I, Amount = A
Amount = Principal + Simple Interest
I = \(\frac{PRT}{100}\)
R = rate, T = time
I = \(\frac{P \times 5 \times 2}{100}\)
I = \(\frac{10P}{100}\)
I = \(\frac{P}{10}\)
Amount A = P + I
5500 = P + \(\frac{P}{10}\)
Multiply through by 100
5500 = 10P + P
5500 = 11P
p = \(\frac{5500}{11}\)
p = ₦5000
If a rod 10cm in length was measured as 10.5cm, calculate the percentage error
5%
5%
8%
7%
Correct answer is A
Actual measurement = 10cm
approximated value of measurement = 10.5cm
% error = \(\frac{\text{Actual measurement − Approximated}}{\text{Actual measure}}\) × 100
= \(\frac{10 − 10.5}{10}\) × 100
= \(\frac{-0.5}{10}\) × 100
ignore -sign i.e take absolute value
= \(\frac{0.5}{10}\) × 100
= 5 %
Evaluate \(\frac{0.00000231}{0.007}\) and leave the answer in standard form
3.3 x 10-4
3.3 x 10-3
3.3 x 10-5
3.3 x 10-8
Correct answer is A
\(\frac{0.00000231}{0.007}\) to standard form
= \(\frac{231 \times 10^{-8}}{7 \times 10^{-3}}\)
= 33 × 10\(^{-8 − (−3)}\)
= 33 × 10\(^{− 8 + 3}\)
= 33 × 10-5
= 3.3 x 10^-4
Find the number of ways that the letters of the word EXCELLENCE be arranged
\(\frac{10!}{2!2!2!}\)
\(\frac{10!}{4!2!}\)
\(\frac{10!}{4!2!2!}\)
\(\frac{10!}{2!2!}\)
Correct answer is C
EXCELLENCE
It is a ten letter word = 10!
Since we have repeating letters, we have to divide to remove the duplicates accordingly. There are 4 Es, 2 Cs, 2 Ls
∴ there are
\(\frac{10!}{4!2!2!}\) ways to arrange