How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
1:00 pm
12:00 noon
11:00 am
10:00 am
Correct answer is C
Let x be the time
Then 72x + 48x = 240
\(\frac{120}{120} \times \frac{240}{120}\)
x = 2hrs
9:00 + 2hrs = 11:00 am
x = \(\frac{6y}{z}\)
x = \(\frac{12y}{z}\)
x = \(\frac{3y}{z}\)
x = \(\frac{3y}{2z}\)
Correct answer is A
\(x\) x \(\frac{y}{z}\)
x = \(\frac{ky}{z}\)
15 = \(\frac{10k}{4}\)
\(\frac{60}{10}\) = k = 6
Therefore; x = \(\frac{6y}{z}\)
Find the quadratic equation whose roots are \(\frac{1}{2}\) and -\(\frac{1}{3}\)
3x\(^2\) + x + 1 = 0
6x\(^2\) + x - 1 = 0
3x\(^2\) + x - 1 = 0
6x\(^2\) - x - 1 = 0
Correct answer is D
x = \(\frac{1}{2}\) and x = \(\frac{-1}{3}\)
(2x - 1) = 0 and (3x + 1) = 0
(2x - 1) (3x + 1) = 0
6x\(^2\) - x - 1 = 0
Make m the subject of the relation k = \(\frac{m - y}{m + 1}\)
m = \(\frac{y + k^2}{k^2 + 1}\)
m = \(\frac{y + k^2}{1 - k^2}\)
m = \(\frac{y - k^2}{k^2 + 1}\)
m = \(\frac{y - k^2}{1 - k^2}\)
Correct answer is B
k = \(\frac{m - y}{m + 1}\)
k\(^2\) = \(\frac{m - y}{m + 1}\)
k\(^2\)m + k\(^2\) = m - y
k\(^2\) + y = m - k\(^2\)m
\(\frac{k^2 + y}{1 - k^2}\) = m\(\frac{(1 - k^2)}{1 - k^2}\)
m = \(\frac{y + k^2}{1 - k^2}\)
Solve \(\frac{1}{3}\)(5 - 3x) < \(\frac{2}{5}\)(3 - 7x)
x > \(\frac{7}{22}\)
x < \(\frac{7}{22}\)
x > \(\frac{-7}{27}\)
x < \(\frac{-7}{27}\)
Correct answer is D
\(\frac{1}{3}\)(5 - 3x) < \(\frac{2}{5}\)(3 - 7x)
5(5 - 3x) < 6(3 - 7x)
25 - 15x < 18 - 42x
- 15x + 42x < 18 - 25
\(\frac{27x}{27}\) < \(\frac{-7}{27}\)
x < \(\frac{-7}{27}\)