How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
If y varies directly as \(\sqrt{n}\) and y = 4 when n = 4, find y when n = 1\(\frac{7}{9}\)
\(\sqrt{17}\)
\(\frac{4}{3}\)
\(\frac{8}{3}\)
\(\frac{2}{3}\)
Correct answer is C
y \(\propto \sqrt{n}\)
y = k\(\sqrt{n}\)
when y = 4, n = 4
4 = k\(\sqrt{4}\)
4 = 2k
k = 2
Therefore,
y = 2\(\sqrt{n}\)
y = 2\(\sqrt{\frac{16}{9}}\)
y = 2\((\frac{4}{3})\)
y = \(\frac{8}{3}\)
Solve for x and y in the equations below
x2 - y2 = 4
x + y = 2
x = 0, y = -2
x = 0, y = 2
x = 2, y = 0
x = -2, y = 0
Correct answer is C
x2 - y2 = 4 .... (1)
x + y = 2 .... (2)
Simplify eqn (1)
(x + y)(x - y) = 4
From eqn (2)
x + y = 2 so substitute it into simplified eqn (1), we have
2 (x - y) = 4
therefore,
x - y = 2 ... (1)
x + y = 2
---------
2x = 4
---------
x = 2, when y = 0
Find the remainder when 2x3 - 11x2 + 8x - 1 is divided by x + 3
-871
-781
-187
-178
Correct answer is D
Hence f(x) = 2x3 - 11x2 + 8x - 1
f(-3) = 2(-3)3 - 11(-3)2 + 8(-3) - 1
= 2(-27) - 11(9) + 8(-3) - 1
= -54 - 99 - 24 - 1
= -178
Make 'n' the subject of the formula if w = \(\frac{v(2 + cn)}{1 - cn}\)
\(\frac{1}{c}(\frac{w - 2v}{v + w})\)
\(\frac{1}{c}(\frac{w - 2v}{v - w})\)
\(\frac{1}{c}(\frac{w + 2v}{v - w})\)
\(\frac{1}{c}(\frac{w + 2v}{v + w})\)
Correct answer is A
w = \(\frac{v(2 + cn)}{1 - cn}\)
2v + cnv = w(1 - cn)
2v + cnv = w - cnw
2v - w = -cnv - cnw
Multiply through by negative sign
-2v + w = cnv + cnw
-2v + w = n(cv + cw)
n = \(\frac{-2v + w}{cv + cw}\)
n = \(\frac{1}{c}\frac{-2v + w}{v + w}\)
Re-arrange...
n = \(\frac{1}{c}\frac{w - 2v}{v + w}\)
1
2
3
4
Correct answer is A
n(f \(\cap\) v) + n(f) + n(v) + n(f \(\cap\) v) = 46
3 + 19 + 23 + x = 46
22 + 23 + x = 46
45 + x = 46
x = 46 - 45
x = 1