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Make 'n' the subject of the formula if w = \(\frac{v(2 + cn)...

Make 'n' the subject of the formula if w = v(2+cn)1cn

A.

1c(w2vv+w)

B.

1c(w2vvw)

C.

1c(w+2vvw)

D.

1c(w+2vv+w)

Correct answer is A

w = v(2+cn)1cn

2v + cnv = w(1 - cn)

2v + cnv = w - cnw

2v - w = -cnv - cnw

Multiply through by negative sign

-2v + w = cnv + cnw

-2v + w = n(cv + cw)

n = 2v+wcv+cw

n = 1c2v+wv+w

Re-arrange...

n = 1cw2vv+w