Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

2,551.

A man is paid r naira per hour for normal work and double rate for overtime. if he does a 35-hour week which includes q hours of overtime, what is his weekly earning in naira?

A.

r(35 + q)

B.

q(35r - q)

C.

q(35 + r)

D.

r(35 + 2q)

Correct answer is D

The cost of normal work = 35r

The cost of overtime = q x 2r = 2qr

The man's total weekly earning = 35r + 2qr

= r(35 + 2q)

2,552.

A market woman sells oil in cylindrical tins 10cm deep and 6cm in diameter at N15.00 each. If she bought a full cylindrical jug 18cm deep and 10cm in diameter for N50.00, how much did she make by selling all the oil?

A.

N62.50

B.

N35.00

C.

N31.00

D.

N25.00

Correct answer is D

V\(\pi\)r2h = \(\pi\)(3)2(10) = 90\(\pi\)cm3

V = \(\pi\)(5)2 x 18 = 450\(\pi\)cm3

No of volume = \(\frac{450\pi}{90\pi}\)

= 5

selling price = 5 x N15 = N75

profit = N75 - N50 = N25.00

2,553.

Find the value of k if \(\frac{k}{\sqrt{3} + \sqrt{2}}\) = k\(\sqrt{3 - 2}\)

A.

3

B.

2

C.

\(\sqrt{3}\)

D.

\(\sqrt 2\)

Correct answer is D

\(\frac{k}{\sqrt{3} + \sqrt{2}}\) = k\(\sqrt{3 - 2}\)

\(\frac{k}{\sqrt{3} + \sqrt{2}}\) x \(\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} - \sqrt{2}}\)

= k\(\sqrt{3 - 2}\)

= k(\(\sqrt{3} - \sqrt{2}\))

= k\(\sqrt{3 - 2}\)

= k\(\sqrt{3}\) - k\(\sqrt{2}\)

= k\(\sqrt{3 - 2}\)

k2 = \(\sqrt{2}\)

k = \(\frac{2}{\sqrt{2}}\)

= \(\sqrt{2}\)

2,554.

Given that log4(Y - 1) + log4(\(\frac{1}{2}\)x) = 1 and log2(y + 1) + log2x = 2, solve for x and y respectively

A.

2, 3

B.

3, 2

C.

-2, -3

D.

-3, -2

Correct answer is C

log4(y - 1) + log4(\(\frac{1}{2}\)x) = 1

log4(y - 1)(\(\frac{1}{2}\)x) \(\to\) (y - 1)(\(\frac{1}{2}\)x) = 4 ........(1)

log2(y + 1) + log2x = 2

log2(y + 1)x = 2 \(\to\) (y + 1)x = 22 = 4.....(ii)

From equation (ii) x = \(\frac{4}{y + 1}\)........(iii)

put equation (iii) in (i) = y (y - 1)[\(\frac{1}{2}(\frac{4}{y - 1}\))] = 4

= 2y - 2

= 4y + 4

2y = -6

y = -3

x = \(\frac{4}{-3 + 1}\)

= \(\frac{4}{-2}\)

X = 2

therefore x = -2, y = -3

2,555.

If b3 = a-2 and c\(\frac{1}{3}\) = a\(\frac{1}{2}\)b, express c in terms of a

A.

a-\(\frac{1}{2}\)

B.

a\(\frac{1}{3}\)

C.

a\(\frac{3}{2}\)

D.

a\(\frac{2}{3}\)

Correct answer is A

c\(\frac{1}{3}\) = a\(\frac{1}{2}\)b

= a\(\frac{1}{2}\)b x a-2

= a-\(\frac{3}{2}\)

= (c\(\frac{1}{3}\))3

= (a-\(\frac{3}{2}\))\(\frac{1}{3}\)

c = a-\(\frac{1}{2}\)