Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

2,521.

If x, y can take values from the set (1, 2, 3, 4), find the probability that the product of x and y is not greater than 6

A.

\(\frac{5}{8}\)

B.

\(\frac{5}{16}\)

C.

\(\frac{1}{2}\)

D.

\(\frac{3}{8}\)

Correct answer is A

\(\begin{vmatrix}& \hline 1 & 2 & 3 & 4\\\hline 1 & 1 & 2& 3 & 4\\2 & 2& 4 & 6 & 8\\ 3& 3& 6& 9 & 12\\4 & 4 & 8 & 12& 16\end{vmatrix}\)

p (product of x, and y \(\leq\) 6) = \(\frac{10}{16}\)

= \(\frac{5}{8}\)

2,522.

In a recent zonal championship games involving 10 teams, teams X and Y were given probabilities \(\frac{2}{5}\) and \(\frac{1}{3}\) respectively of winning the gold in the football event. What is the probability that either team will win the gold?

A.

\(\frac{2}{15}\)

B.

\(\frac{7}{15}\)

C.

\(\frac{11}{15}\)

D.

\(\frac{13}{15}\)

Correct answer is C

p(x) = \(\frac{2}{5}\) p(y) = \(\frac{1}{3}\)

p(x or y) = p(x ∪ y)

= p(x) + p(y)

= \(\frac{2}{5}\) + \(\frac{1}{3}\)

= \(\frac{11}{5}\)

2,523.

A bag contains 16 red balls and 20 blue balls only. How many white balls must be added to the bag so that the probability of randomly picking a red ball is equal to \(\frac{2}{5}\)

A.

4

B.

20

C.

24

D.

40

Correct answer is A

Number of red balls = 16,

Number of blue balls = 20

Let x represent the No of white balls to be added

∴ Total number of balls = 36 + x

2(36 + x) = 80

= 2x + 80 - 72

= 8

x = \(\frac{8}{2}\)

= 4

2,524.

Find the positive value of x if the standard deviation of the numbers 1, x + 1, 2x + 1 is 6

A.

1

B.

2

C.

3

D.

4

Correct answer is C

mean (x) = \(\frac{1 + x + 1 + 2x + 1}{3}\)

= \(\frac{3x + 3}{3}\)

= 1 + x

\(\begin{array}{c|c} X & (X -X) & (X -X)^2\\ \hline 1 & -x & x^2 \\ x + 1 & 0 & 0\\2x + 1 & x & x^2\\ \hline & & 2x^2\end{array}\)

S.D = \(\sqrt{\frac{\sum(x - 7)^2}{\sum f}}\)

= \(\sqrt{(6)}^2\)

= \(\frac{2x^2}{3}\)

= 2x2

= 18

x2 = 9

∴ x = \(\pm\) \(\sqrt{9}\)

= \(\pm\)3

2,525.

Find the variance of the numbers k, k+1, k+2,

A.

\(\frac{2}{3}\)

B.

1

C.

k + 1

D.

(k + 1)2

Correct answer is A

mean (x) = \(\frac{\sum x}{N}\)

= k + k + 1 + k + 3

= \(\frac{3k + 3}{3}\)

= k + 1

\(\begin{array}{c|c} X & (X -X) & (X -X)^2\\ \hline k & -1 & 1 \\ k + 1 & 0 & 0\\ k + 2 & 1 \\ \hline & & 2\end{array}\)

Variance (52) = \(\frac{\sum (x - x)^2}{N}\)

= \(\frac{2}{3}\)