How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
\(\frac{5√3m}{3}\)
5√3m
10√3m
\(\frac{10√3m}{3}\)
Correct answer is C
RQP = 90o
PQS = 30o but
RQS = 90o = \(\frac{RS}{10}\)
RS = 10 tan 60o
RS = 10 tan 60o
RS = 10√3m
If M(4, q) is the mid-point of the line joining L(p, -2) and N(q, p). Find the values of p and q
P = 2, q = 4
p = 3, q = 1
p = 5, q = 3
p = 6, q = 2
Correct answer is D
\(\frac{p + q}{2}\) = 4
p + q = 8 ....(i)
\(\frac{p - 2}{2}\) = q
p - 2q 2 ....(ii)
q = 2, p = 6
3q = 6
the perpendicular bisector of XY
a right-angled triangle
a circle
a semi circle
Correct answer is D
Since XY is a fixed line and
XPY = 90o P is on one side of XY
P1P2P3......Pn are all possible cases where
XPY = 90o the only possible tendency is a semicircle because angles in semicircle equals 90o
Calculate the perimeter, in cm, of a sector of a circle of radius 8cm and angle 45o
2\(\pi\)
8 + 2\(\pi\)
16 + 2\(\pi\)
16 + 16\(\pi\)
Correct answer is C
Perimeter = OP + OQ + PQ
= 8 + 8 + PQ
length PQ = \(\frac{\theta}{360 \times 2\pi r}\)
= \(\frac{45}{360}\) x 2 x \(\pi\) x 8
= 2\(\pi\)
Perimeter of sector 2r + L
Where l = length of arc and r = radius
∴ P = 2(8) + 2\(\pi\)
= 16 + 2\(\pi\)
11 520cm3
36 000cm3
38 200cm3
47 520cm3
Correct answer is A
Internal dimension are 50cm, 36cm and 20cm
internal volume = 50 x 36 x 20cm3
1000 x 36cm3
= 36000cm3
External dimension are 54cm x 40cm x 22cm
= 2160cm2 x 22cm = 47520cm3
Volume of wood = Ext. volume - Int. volume
= 47,520cm3 - 36,000cm3
= 11,520cm3