the perpendicular bisector of XY
a right-angled triangle
a circle
a semi circle
Correct answer is D
Since XY is a fixed line and
XPY = 90o P is on one side of XY
P1P2P3......Pn are all possible cases where
XPY = 90o the only possible tendency is a semicircle because angles in semicircle equals 90o
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