What is the locus of a point P which moves on one side of a straight line XY, so that the angle XPY is always equal to 90^o?

the perpendicular bisector of XY

a right-angled triangle

a circle

a semi circle

Correct answer is D

Since XY is a fixed line and

XPY = 90^o P is on one side of XY

P₁P₂P₃......Pⁿ are all possible cases where

XPY = 90^o the only possible tendency is a semicircle because angles in semicircle equals 90^o

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What is the locus of a point P which moves on one side of a straight line XY, so that the angle XPY is always equal to 90o?

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What is the locus of a point P which moves on one side of a straight line XY, so that the angle XPY is always equal to 90^o?