How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
5cm
4cm
3√3 cm
\(\frac{10\sqrt{3}}{3}\)cm
Correct answer is D
Let each of the unknown side be x.
\(10^{2} = x^{2} + x^{2} - 2(x)(x) \cos 120\)
\(100 = 2x^{2} - 2x^{2} \cos 120\)
\(100 = 2x^{2} + x^{2} = 3x^{2}\)
x = \(\sqrt{\frac{100}{3}}\)
= \(\frac{10}{\sqrt{3}}\) x \(\frac{\sqrt{3}}{\sqrt{3}}\)
x = \(\frac{10\sqrt{3}}{3}\)cm
If sin \(\theta\) = cos \(\theta\), find \(\theta\) between 0° and 360°
45o, 225o
135o, 315o
45o, 315o
135o, 225o
Correct answer is A
sin \(\theta\) = cos \(\theta\) 0 \(\leq\) \(\theta\) \(\leq\) 360°
The acute angle where sin \(\theta\) = cos \(\theta\) = 45°
But at the third Quadrant Cos \(\theta\) = -ve; sin \(\theta\) = -ve.
at the 3rd quadrant, value with respect to Q is
(180 + Q) where Q = acute angle
(180 + 45) = 225°
The two solution are 45°, 225°
The angle between latitudes 30oS and 13oN is
17o
33o
43o
53o
Correct answer is C
The angle between 2 latitudes one in northern hemisphere and the other in southern hemisphere and the other in southern hemisphere is the sum of their latitudes.
∴ Total angle difference = (30 + 13) = 43o
Find the area of the sector of a circle with radius 3m, if the angle of the sector is 60o
4.0m2
1m2
4.7m2
5.0m2
Correct answer is C
Area of sector
\(\frac{\theta}{360}\) x \(\pi\)r2, \(\theta\) = 60o, r = 3m
= \(\frac{60}{360}\) x \(\frac{12}{7}\) x 3 x 3
\(\frac{1}{6}\) x \(\frac{22}{7}\) x 9
= \(\frac{33}{7}\)
= 4.7m2
find the radius of a sphere whose surface area is 154cm2 (\(\pi = \frac{22}{7}\))
7.00cm
3.50cm
3.00cm
1.75cm
Correct answer is B
Surface area = 154cm2 (area of sphere)
4\(\pi\)r2 = 154
r\(\sqrt{\frac{154}{4\pi}}\)
= 3.50cm