If sin \(\theta\) = cos \(\theta\), find \(\theta\) between 0° and 360°

A.

45o, 225o

B.

135o, 315o

C.

45o, 315o

D.

135o, 225o

Correct answer is A

sin \(\theta\) = cos \(\theta\) 0 \(\leq\) \(\theta\) \(\leq\) 360°

The acute angle where sin \(\theta\) = cos \(\theta\) = 45°

But at the third Quadrant Cos \(\theta\) = -ve; sin \(\theta\) = -ve.

at the 3rd quadrant, value with respect to Q is

(180 + Q) where Q = acute angle

(180 + 45) = 225°

The two solution are 45°, 225°