Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

2,071.

John gives one-third of his money to Janet who has N105.00. He then finds that his money is reduced to one-fourth of what Janet now has. Find how much money john has at first

A.

N45.00

B.

N48.00

C.

N52.00

D.

N60.00

E.

N52.00

Correct answer is A

Let x be John's money, Janet already had N105, \(\frac{1}{3}\) of x was given to Janet

Janet now has \(\frac{1}{3^2}\)x + 105 = \(\frac{x + 315}{3}\)

John's money left = \(\frac{2}{3}\)x

= \(\frac{\frac{1}{4}(x + 315)}{3}\)

= \(\frac{2}{3}\)

24x = 3x + 945

∴ x = 45

2,072.

Find correct to two decimals places 100 + \(\frac{1}{100}\) + \(\frac{3}{1000}\) + \(\frac{27}{10000}\)

A.

100.02

B.

1000.02

C.

100.22

D.

100.01

E.

100.51

Correct answer is A

100 + \(\frac{1}{100}\) + \(\frac{3}{1000}\) + \(\frac{27}{10000}\)

\(\frac{1000,000 + 100 + 30 + 27}{10000}\) = \(\frac{1,000.157}{10000}\)

= 100.02

2,073.

List all integers satisfying the inequality -2 \(\leq\) 2 x -6 < 4

A.

2, 3, 4, 5

B.

2, 3, 4

C.

2, 5

D.

3, 4, 5

E.

4, 5

Correct answer is B

-2 \(\leq\) 2x - 6 < 4 = 2x - 6 < 4

= 2x < 10

= x < 5

2x \(\geq\) -2 + 6 \(\geq\)

= x \(\geq\) 2

∴ 2 \(\leq\) x < 5 [2, 3, 4]

2,074.

In the equation below, Solve for x if all the numbers are in base 2: \(\frac{11}{x}\) = \(\frac{1000}{x + 101}\)

A.

101

B.

11

C.

110

D.

111

E.

10

Correct answer is B

\(\frac{11}{x}\) = \(\frac{1000}{x + 101}\) = 11(x + 101)

1000x = 11x + 1111

1000x - 11x = 1111

101x = 1111

x = \(\frac{1111}{101}\)

x = 11

2,075.

A sum of money was invested at 8% per annum simple interest. If after 4 years the money amounts to N330.00. Find the amount originally invested

A.

N180.00

B.

N165.00

C.

N150.00

D.

N250.00

E.

N200.00

Correct answer is D

S.I = \(\frac{PTR}{100}\)

T = 4yrs, R = 8%, a = N330.00

330 - P = \(\frac{PTR}{100}\), A = P + I

i.e. A = P + \(\frac{PTR}{100}\)

330 = P + \(\frac{P(4) (8)}{100}\)

33000 = 32P + 100p

132P = 33000

P = N250.00