How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Make x the subject of the equation a(b + c) + \(\frac{5}{d}\) - 2 = 0
c = \(\frac{2d - 5 - b}{ad}\)
c = \(\frac{2d - 5 - abd}{ad}\)
c = \(\frac{2d - 5 - ab}{ad}\)
c = \(\frac{5 - 2d - b}{ad}\)
Correct answer is B
a(b + c) + \(\frac{5}{d}\) - 2 = 0
ab + ac + \(\frac{5}{d}\) - 2 = 0
abd + \(\frac{acd}{d}\) + 5 - 2 = ab + ac + 5 - 2d
acd = 2d - 5 - abd
c = \(\frac{2d - 5 - abd}{ad}\)
PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If < PQS = 15o find < QRS
75o
37\(\frac{1}{2}\)o
127\(\frac{1}{2}\)o
105o
Correct answer is D
PSO = 90o(angle in a semicircle)
SPO = 180o - (90o + 15o) = 75o
< QRS = 108o - 75o
= 105o(opposite angles in cyclic quadrilateral are supplementary)
One of the following statements is wrong. Which is it?
If a triangle is equiangular then it is also equilateral
If a triangle is equilateral then it is also then it is also equiangular
If two triangles are similar then they are also congurent
The sum of the interior angles of any triangle is 180 degrees
Correct answer is C
Two similar triangles are not also congruent
Simplify 2\(\frac{5}{12}\) - 1\(\frac{7}{8}\) x \(\frac{6}{5}\)
\(\frac{1}{6}\)
\(\frac{13}{20}\)
\(\frac{11}{30}\)
\(\frac{9}{4}\)
\(\frac{5}{3}\)
Correct answer is A
2\(\frac{5}{12}\) - 1\(\frac{7}{8}\) x \(\frac{6}{5}\) = \(\frac{29}{12}\) - \(\frac{15}{8}\) x \(\frac{6}{5}\)
= \(\frac{29}{12}\) - \(\frac{9}{4}\)
= \(\frac{29 - 27}{12}\)
= \(\frac{2}{12}\)
= \(\frac{1}{6}\)
1m
1.1m
1.2m
0.9m
1.3m
Correct answer is E
If tan\(\theta\) = 2, 4
\(\theta\) = tan-1(2.4)
= 67o 25
By sin formula \(\frac{x}{sin 90^o}\) = \(\frac{50}{sin 22^o 37}\)
= \(\frac{50}{sin(9o - \theta)}\)
sin90o = 1
x = 50 cosec 22o 37
= 50 x 2.604x
= 130cm
but 100cm = 1m
130cm = 1.3m