How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
12cm2
28\(\frac{1}{2}\)cm2
16cm2
10cm2
6cm2
Correct answer is E
Area of the triangle XYZ = \(\frac{1}{2}\)bh = \(\frac{1}{2}\)ZY x XY
= \(\frac{1}{2}\) x 3 x 4
= 6cm2.
In the figure, find x in terms of a, b and c.
a + b + c
180o - (a + b + c)
a - b - c
a + b
a + c
Correct answer is A
180 - x + a + b + c
= 180(sum of interior angle in triangle)
a + b + c = x.
In the figure, find the area of XYZW
60cm2
54cm2
36cm2
54\(\sqrt{2}\)cm2
27\(\sqrt{2}\)cm2
Correct answer is C
Average of trapezium XYZW = \(\frac{1}{2}\)(a + b)h from rt < YDZ,
h = 8 sin 30º
area = \(\frac{1}{2}\)(10 + 8)4
= 8 x \(\frac{1}{2}\) = 4
\(\frac{1}{2}\)(18) x 4
= 36cm2
50o
75o
35o
115o
30o
Correct answer is C
< WYT = \(\frac{180 - 30}{2}\)
= \(\frac{150}{2}\)
= 75o(base angles of isosceles D)
YXW = 75 - 40 = 35o(Exterior angle is equal to sum of interior angles)
Find the area of the shades segments in the figure
\(\sqrt{3}\)
4 \(\pi - \sqrt{3}\)
-\(\frac{2}{3} \pi\)
\(\frac{2\pi}{3}\) -3
Correct answer is D
Area of section = \(\frac{60^o}{360^o}\) x 11r2
= \(\frac{60}{360} \times \pi \times 2^2\)
= \(\frac{1}{6}\) x 4
= \(\frac{4\pi}{6}\)
= \(\frac{2\pi}{3}\)
Area of triangle = \(\frac{1}{2x}\)
= 2 x 28.......60
Segment Area = Area of section - Area of triangle
= \(\frac{2\pi}{3}\) -3