How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
From the venn diagram above, the shaded parts represent
(P\(\cap\)Q)\(\cup\)(P\(\cap\)R)
(P\(\cup\)Q)\(\cap\)(P\(\cap\)R)
(P\(\cup\)Q)\(\cup\)(P\(\cup\)R)
(P\(\cap\)Q)\(\cup\)(P\(\cup\)R)
Correct answer is A
No explanation has been provided for this answer.
30
11
50
20
Correct answer is B
5x° + (16x - 24)° + 5x° + (4x + 12)° + (6x + 12)° = 360°
36x° - 24 + 12 + 12 = 360°
36x° = 360°
x° = \(\frac{360°}{36}\)
= 10°
Thus, the angle of sector representing Mathematics is 5 x 10° = 50°. Hence the number of students who offer mathematics is
\(\frac{50}{360} \times 80 \approx 11\)
460mins
720mins
960mins
200mins
Correct answer is B
80 + 160 + 200 + 80 + 128 + 72 = 720minutes
The value x in the figure given is
110o
100o
70o
130o
Correct answer is D
Sum of the angles in a triangle = 180°
180° - x + 60 + 70 = 180
130° - x = 180° - 180° = 0°
x = 130°
In the diagram given, find the value of x.
30o
40o
45o
15o
Correct answer is B
In the diagram above, < CDE = < CED = 15o
(base < s of isos. \(\bigtriangleup\))
< ECD = 180o - (15 + 15)o
= 180o - 30o = 150o
But x + 110o = 150o
(Sum of opp. interior < s of a\(\bigtriangleup\) = opp. exterior < )
x = 150o - 110o = 40o