How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
25o
65o
115o
130o
Correct answer is B
x = 65o (An interior angle of a cyclic quadrilateral = opposite exterior angle).
1:2
2:1
1:2
3:1
Correct answer is B
From the diagram, XYZQ is a parallelogram. Thus, |YZ| = |XQ| = |PX|; \(\bigtriangleup\)PXY, Let the area of XYZQ = A1, the area of \(\bigtriangleup\)PXY
= Area of \(\bigtriangleup\)YZR = A2
Area of \(\bigtriangleup\)PQR = A = A1 + 2A2
But from similarity of triangles
\(\frac{\text{Area of PQR}}{\text{Area of PXY}} = (\frac{PQ}{PX})^2 = (\frac{QR}{XY})^2\)
\(\frac{A}{A_2} = (\frac{2}{1})^2 = \frac{2}{1}\)
A = 4A2 But, A = A1 + 2A
A1 = 4A2 - 2A2
A1 = 2A2
\(\frac{A_1}{A_2}\) = 2
A1:A2 = 2:1
Area of XYZQ:Area of \(\bigtriangleup\)YZR = 2:1
In the diagram, PQ//RS, QU//PT and < PSR = 42o. Find angle x.
84o
48o
42o
32o
Correct answer is C
From the diagram, < QPS = xo (Corresponding angles)
Also, < QPS = < PSR(Alternate angles)
x = 42o
In the figure shown, PQs is a straight line. What is the value of < PRQ?
128o
108o
98o
78o
Correct answer is D
< QPR + < PRQ = < RQS
(Sum of two interior angles of a triangle = Opposite exterior angles)
70o + < PRQ = 148
< PRQ = 148o - 70o
= 78o
34cm
52cm
56cm
96cm
Correct answer is B
For a rhombus, all the sides are equal and diagonals bisect each other at 90o. Hence, the triangles formed are congruent: (under RHS).
Thus: \(\bar{PS}^2\) = 52 + 122
\(\bar{PS} = \sqrt{25 + 144}\)
= \(\sqrt{169}\)
\(\bar{PS}\) = 13cm
perimeter = 4 x length of a side
= 4 x 13cm
= 52cm