How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
In the diagram, QR//ST, /PQ/ = /PR/ and < PST = 75o. Find the value of y
105o
110o
130o
150o
Correct answer is A
In \(\bigtriangleup\) PQR,
Q = S = 75o (Corresponding angle)
R = Q = 75o (Base angles of an isosceles \(\bigtriangleup\))
But, y + 75o = 180o (Sum of angles in a straight line)
y = 180 - 75
y = 105o
What is the value of m in the diagram?
20o
30o
40o
50o
Correct answer is B
4m - 15o = m + 75o
(Vertically opposite angles are equal)
4m - m = 75 + 15
3m = 90
m = \(\frac{90}{3}\)
m = 30o
55\(\frac{1}{3}\)%
60%
65%
66\(\frac{2}{3}\)%
Correct answer is D
Percentage of students with marks ranging from 35 to 50 = \(\frac{f_{35} + f{40} + f{50}}{\sum f}\)
= \(\frac{35 + 40 + 45}{20 + 35 + 40 + 45 + 25 + 15}\) x 100%
= \(\frac{120}{180}\) x 100%
= 66\(\frac{2}{3}\)%
100
85
80
70
Correct answer is B
Pass mark = 50%
No. of students that passed = f50 + f65 + f80
= 45 + 25 + 15
= 85
In the diagram, < PSR = 220o, < SPQ = 58o and < PQR = 41o. Calculate the obtuse angle QRS.
90o
100o
121o
60o
Correct answer is C
Joining SQ. In \(\bigtriangleup\) SPQ,
(22o + a) + 55o + (41o + b) = 180o
121o + a + b = 180o
a + b = 180 - 121
a + b = 59o.....(1)
In \(\bigtriangleup\) SRPQ; R + a + b = 180o
R + 59o = 180o
(in (1), a + b = 59o)
R = 180 - 59
R = 121o