How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Simplify 1\(\frac{3}{4} - (2 \frac{1}{3} + 4)\)
3\(\frac{5}{12}\)
2\(\frac{7}{12}\)
-4 \(\frac{7}{12}\)
-5 \(\frac{7}{12}\)
Correct answer is C
1\(\frac{3}{4} - (2 \frac{1}{3} + 4)\) = \(\frac{7}{4} - (\frac{7}{3} + \frac{4}{1})\); \(\frac{7 + 12}{3}\)
\(\frac{7}{4} - \frac{19}{3} = \frac{21 + 76}{12}\)
= \(\frac{-55}{12} = -4 \frac{7}{12}\)
What must be added to (2x - 3y) to get (x - 2y)?
5y - x
y - x
x - 5x
x - y
Correct answer is B
What must be added to 2x - 3y = Difference between x - 2y and 2x - 3y
x - 2y - 2y - (2x - 3y); x - 2y - 2x + 3y
= x - 2x + 3y - 2y
= y - x
Given that n(p) = 19, m(P \(\cup\) Q) = 38 and n(P \(\cap\) Q) = 7, Find n(C)
26
31
36
50
Correct answer is A
n(P \(\cup\) Q) = m(P \(\cap\) C)
38 = 19 = n(C) - 7
n(C) = 38 - 12
= 26
G varies directly as the square of H, If G is 4 when H is 3, find H when G = 100
15
25
75
225
Correct answer is A
G \(\alpha\) H2
G = KH2
4 = K(3)2
4 = 9k; K = \(\frac{4}{9}\)
100 = \(\frac{4}{9}H^2\)
4H2 = 900
H2 = \(\frac{900}{4}\)
H2 = 225
H = \(\sqrt{225}\)
H = 15
If \(\sqrt{72} + \sqrt{32} - 3 \sqrt{18} = x \sqrt{8}\), Find the value of x
1
\(\frac{3}{4}\)
\(\frac{1}{2}\)
\(\frac{1}{4}\)
Correct answer is C
\(\sqrt{2} + \sqrt{32} - 3\sqrt{18} = x\sqrt{8}\)
= \(\sqrt{36 \times 2} + \sqrt{16 \times 2} - 3\sqrt{2 \times 9}\)
= x\(\sqrt{2 \times 4}\)
= 6\(\sqrt{2} + 4\sqrt{2} - 9\sqrt{2} = 2 \times \sqrt{2}\)
\(\sqrt{2} (6 + 4 - 9) = 2x\sqrt{2}\)
\(\sqrt{2} = 2x \sqrt{2}\) divide both sides by \(\sqrt{2}\)
\(\frac{\sqrt{2}}{\sqrt{2}} = \frac{2 \times \sqrt{2}}{\sqrt{2}}\)
1 = 2x
2x = 1
x = \(\frac{1}{2}\)