Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

1,256.

The sum of the interior angles of regular polygon is 1800o. How many sides has the polygon?

A.

16

B.

12

C.

10

D.

8

Correct answer is B

Sum = (n - 2)180

1800 = (n - 2)180

divide both sides by 180o

\(\frac{1800}{180}\) = (n - 2)\(\frac{180}{180}\)

10 = n - 2

10 + 2 = n

n = 12

1,257.

Solve (\(\frac{27}{125}\))-\(\frac{1}{3}\) x (\(\frac{4}{9}\))\(\frac{1}{2}\)

A.

\(\frac{10}{9}\)

B.

\(\frac{9}{10}\)

C.

\(\frac{2}{5}\)

D.

\(\frac{12}{125}\)

Correct answer is A

(\(\frac{27}{125}\))-\(\frac{1}{3}\) x (\(\frac{4}{9}\))\(\frac{1}{2}\)

= (\(\frac{3^3}{5^3}\))-\(\frac{1}{3}\)-\(\frac{1}{3}\) x (\(\frac{3^2}{3^2}\))\(\frac{1}{2}\) -\(\frac{1}{2}\)

= \(\frac{3^{-1}}{3^{-1}} \times \frac{2}{3}\)

= \(\frac{\frac{1}{3}}{\frac{1}{5}} \times \frac{2}{3}\)

\(\frac{1}{3} \times \frac{5}{1} \times {2}{3} = \frac{10}{9}\)

1,258.

Alfred spent \(\frac{1}{4}\) of his money on food, \(\frac{1}{3}\) on clothing and save the rest. If he saved N72,20.00, how much did he spend on food?

A.

N43,200.00

B.

N43,000.00

C.

N42,200.00

D.

N40,000.00

Correct answer is A

let the total amount be Nx i.e (\(\frac{1}{4}\))x + (\(\frac{1}{3}\))x + 72,000 = x

\(\frac{x}{4} + \frac{x}{4} + 72,000 = x\)

\(\frac{3x + 4x + 86,400}{12} = x\)

cross multiply to clear fraction

12x = 3x + 4x + 86,400

12x - 7x = 86,400

5x = 86,400

x - \(\frac{86,400}{5}\) = 172,800

amount spent on food = \(\frac{1}{4} \times 172,800\)

= N43,200

1,259.

If p = {prime factors of 210} and Q = {prime less than 10}, find p \(\cap\) Q

A.

{1,2, 3}

B.

{2, 3, 5}

C.

{1, 3, 5,7}

D.

{2,3,5,7}

Correct answer is D

prime factor of 210 = 2, 3, 5, 7

prime numbers less than 10 = 2, 3, 5 , 7

1,260.

Express 3 - [\(\frac{x - y}{y}\)] as a single fraction

A.

\(\frac{3xy}{y}\)

B.

\(\frac{x - 4y}{y}\)

C.

\(\frac{4y - x}{y}\)

D.

3 - \(\frac{x - y}{y}\)

Correct answer is C

(\(\frac{x -y}{y}\)); \(\frac{3}{1} - \frac{x y}{y}\)

= \(\frac{3y - (x - y)}{y}\)

= \(\frac{3y - x + y}{y}\)

= \(\frac{4y - x}{y}\)