How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
2\(\sqrt{21}\)cm
\(\sqrt{42}\)cm
2\(\sqrt{19}\)cm
\(\sqrt{21}\)cm
Correct answer is A
From \(\bigtriangleup\) OMQ find /MQ/ by Pythagoras OQ2 = OM2 + MQ2
52 = 22 + MQ2
25 = 4 + MQ2
25 - 4 = MQ2
21 - MQ2
MQ2 = 21
MQ2 = \(\sqrt{21}\)
Length of chord = 2 x \(\sqrt{21}\) = 2\(\sqrt{21}\)cm
Given that p\(\frac{1}{3}\) = \(\frac{3\sqrt{q}}{r}\), make q the subject of the equation
q = p\(\sqrt{r}\)
q = p3r
q = pr3
q = pr\(\frac{1}{3}\)
Correct answer is D
p\(\frac{1}{3}\) = \(\frac{3\sqrt{q}}{r}\)(cross multiply)
3\(\sqrt{q}\) = r x 3\(\frac{\sqrt{q}}{r}\)(cross multiply)
3\(\sqrt{q}\) = r x 3\(\sqrt{p}\) cube root both side
q = 3\(\sqrt{r}\) x p
q = r\(\frac{1}{3}\)p = pr\(\frac{1}{3}\)
If \(\frac{1}{2}\)x + 2y = 3 and \(\frac{3}{2}\)x and \(\frac{3}{2}\)x - 2y = 1, find (x + y)
3
2
1
5
Correct answer is A
\(\frac{1}{2}\)x + 2y = 3......(i)(multiply by 2)
\(\frac{3}{2}\)x - 2y = 1......(ii)(multiply by 2)
x + 4y = 6......(iii)
3x - 4y = 2.....(iv) add (iii) and (iv)
4x = 8, x = \(\frac{8}{4}\) = 2
substitute x = 2 into equation (iii)
x + 4y = 6
2 + 4y = 6
4y = 6 - 2
4y = 4
y = \(\frac{4}{4}\)
= 1(x + y)
2 + 1 = 3
If x = 64 and y = 27, evaluate: \(\frac{x^{\frac{1}{2}} - y^{\frac{1}{3}}}{y - x^{\frac{2}{3}}}\)
2\(\frac{1}{5}\)
1
\(\frac{5}{11}\)
\(\frac{11}{43}\)
Correct answer is C
\(\frac{x^{\frac{1}{2}} - y^{\frac{1}{3}}}{y - x^{\frac{2}{3}}}\)
substitute x = 64 and y = 27
\(\frac{64^{\frac{1}{2}} - 27^{\frac{1}{3}}}{27 - 64^{\frac{2}{3}}} = \frac{\sqrt{64} - 3\sqrt{27}}{27 - (3\sqrt{64})^2}\)
= \(\frac{8 - 3}{27 - 16}\)
= \(\frac{5}{11}\)
Solve the inequality: \(\frac{2x - 5}{2} < (2 - x)\)
x > 0
x < \(\frac{1}{4}\)
x > 2\(\frac{1}{2}\)
x < 2\(\frac{1}{4}\)
Correct answer is D
\(\frac{2x - 5}{2} < \frac{(2 - x)}{1}\)
2x - 5 < 4 - 2x
2x + 2x < 4 + 5
4x < 9
x < \(\frac{9}{4}\)
x < 2\(\frac{1}{4}\)