How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Given that P = x2 + 4x - 2, Q = 2x - 1 and Q - p = 2, find x
-2
-1
1
2
Correct answer is B
P = x2 + 4x - 2, Q = 2x - 1
Q - p = 2, (2x - 1) - (x2 + 4x - 2) = 2
2x - 1 - x2 - 4x + 2 = 2
-2x - x2 + 1
-x2 - 2x - 1 = 0
x2 + 2x + 1 = 0
x2 + x + x + 1 = 0
x(x + 1) + 1(x + 1) = 0
(x + 1)(x + 1) = 0
x + 1 = 0 or x + 1 = 0
x = -1 or x = -1
x = -1
15
12
9
6
Correct answer is B
Let the interior angle = xo
interior angle = 5xo (sum of int. angle ann exterior)
(angles = angle or straight line)
6x = 180
x = \(\frac{180}{6}\)
x = 30o
no. of sides = \(\frac{\text{sum of exterior angles}}{\text{exterior angle}}\)
= \(\frac{360}{30}\) = 12
Express \(\frac{2}{x + 3} - \frac{1}{x - 2}\) as a simple fraction
\(\frac{x - 7}{x^2 + x - 6}\)
\(\frac{x - 1}{x^2 + x - 6}\)
\(\frac{x - 2}{x^2 + x - 6}\)
\(\frac{x - 27}{x^2 + x - 6}\)
Correct answer is A
\(\frac{2}{x + 3} - \frac{1}{x - 2}\) = \(\frac{2(x - 2) - (x - 3)}{(x + 3) (x - 2)}\)
= \(\frac{2x - 4 - x - 3}{x^2 - 2x + 3x - 6}\)
= \(\frac{x -7}{x^2 + x - 6}\)
= \(\frac{x - 7}{x^2 + x - 6}\)
11
\(\frac{15}{2}\)
5
\(\frac{5}{2}\)
Correct answer is C
Let the number be y, subtract y from 2 i.e 2 - y
2 - y = 4 < \(\frac{1}{5}\) y,
2 - y = \(\frac{y}{5}\) - 4
2 - y + 4 = \(\frac{y}{5}\)
6 = \(\frac{y}{5}\) + y
6 = \(\frac{y + 5y}{5}\)
6 = \(\frac{6y}{5}\)
multiplying through by 5
6 * 5 = 6y
\(\frac{30}{6}\) = y
= 5
the bisector of the straight line joining P and M
an arc of a circle with PM as a chord
the bisector of angle PXM
a circle centre X and radius PM
Correct answer is B
No explanation has been provided for this answer.