Mathematics Questions & Answers - Free Online Practice

1,186.

Correct answer is A

23_x = 32₅

2 \(\times x^1 + 3 \times x^0 = 3 \times 5^1 + 2 \times 5^0\)

= 2x + 3 = 15 + 2

2x + 3 = 17

2x = 17 - 3

2x = 14

x = \(\frac{14}{2}\)

x = 7

1,187.

Simplify 10\(\frac{2}{5} - 6 \frac{2}{3} + 3\)

6\(\frac{4}{15}\)

6\(\frac{11}{15}\)

7\(\frac{4}{15}\)

7\(\frac{11}{15}\)

View answer & explanation

Correct answer is B

10\(\frac{2}{5} - 6 \frac{2}{3} + 3\)

\(\frac{52}{5} - \frac{20}{3} + \frac{3}{1}\)

= \(\frac{156 - 100 + 45}{15}\)

\(\frac{156 + 45 - 100}{15}\)

= \(\frac{201 - 100}{15}\)

= \(\frac{101}{15}\)

= 6\(\frac{11}{15}\)

1,188.

Using the venn diagram, find n(x \(\cap\) y¹)

View answer & explanation

Correct answer is A

(x \(\cap\) y²) = [a, b]

n(x \(\cap\) y²) = 2

1,189.

In the diagram, ST//PQ reflex angle SRQ = 198^o and < RQp = 72^o. Find the value of y

18^o

54^o

87^o

92^o

View answer & explanation

Correct answer is B

R +198 = 360(angles at a point)

R = 360 - 198 = 162^o

C = 72(alternate angle), b + c = 180(angles or straight line)

b = 190 - c = 180 - 72 = 108

a + b = R = 162

a = R - b = 162 - 108

= 54, but a = y(alternate angles)

y = 54^o

1,190.

In the diagram, PQ is a straight line. Calculate the value of the angle labelled 2y

130^o

120^o

110^o

100^o

View answer & explanation

Correct answer is D

Sum of angles on straight line = 180^o

80^o + 50^o + x + 10^o = 180^o

140^o + x = 180^o

x = 180^o - 140^o

x = 40^o

total sum of all angles = 360^o

2y^o + 2x^o + 80^o + 50^o + x + 10^o = 360^o

2y^o + 2(40)^o + 80^o + 50^o + 40 + 10 = 360^o

2y^o + 80 + 180^o = 360^o

2y^o + 260^o = 360^o

2y^o = 360^o - 260^o

2y^o = 100^o

angle 2y^o = 100^o