In the diagram, ST//PQ reflex angle SRQ = 198o and < RQp = 72o. Find the value of y
A.
18o
B.
54o
C.
87o
D.
92o
Correct answer is B
R +198 = 360(angles at a point)
R = 360 - 198 = 162o
C = 72(alternate angle), b + c = 180(angles or straight line)
b = 190 - c = 180 - 72 = 108
a + b = R = 162
a = R - b = 162 - 108
= 54, but a = y(alternate angles)
y = 54o