Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

1,121.

The extension of a stretched string is directly proportional to its tension. If the extension produced by a tension of 8 Newton’s is 2cm, find the extension produced by a tension of 12 newton’s.

A.

2

B.

1

C.

0

D.

3

Correct answer is D

Let the extension be E and the tension be T.

Then \(E \propto T\)

\(E = kT\)

when T = 8N, E = 2cm

\(2 = k \times 8\)

\(k = \frac{2}{8} = 0.25\)

\(\therefore E = 0.25T\)

when T = 12N, \(E = 0.25 \times 12 = 3cm\)

1,122.

Given that A = {1, 5, 7} B = {3, 9, 12, 15} C = {2, 4, 6, 8} Find (A ∪ B) ∪ C

A.

{1, 2, 3, 4, 5, 6, 7, 8, 9, 12, 15}

B.

{1, 2, 3, 5, 6, 8, 12, 15}

C.

{2, 4, 5, 9, 12, 15}

D.

{1, 5, 6, 7, 8, 9, 12, 15}

Correct answer is A

{A ∪ B ∪ C}

{A ∪ B} = {1, 3, 5, 7, 9, 12, 15}

∪ C={2,4,6,8}

{A ∪ B} ∪ C = {1, 3, 5, 7, 9, 12, 15} ∪ {2, 4, 6, 8}

= {1, 2, 3, 4, 5, 6, 7, 8, 9, 12, 15}

{A ∪ B} ∪ C = {1, 2, 3, 4, 5, 6, 7, 8, 9, 12, 15}

1,123.

Find at which rate per annum simple interest N525 will amount to N588 in 3 years.

A.

3%

B.

2%

C.

5%

D.

4%

Correct answer is D

I = A − P

= N588 − N525

∴I = N63

I = PRT ÷ 100

R = [100I ÷PT]

R = [(100 × 63 ) ÷ (525 × 3)]

= (6300 ÷ 1575) = 4

∴ The rate = 4 %

1,124.

If log520 = x, find x

A.

1.761

B.

1.354

C.

1.861

D.

2.549

Correct answer is C

log520 = x

5x = 20(Take log10 of both sides)

log5x = log20

xlog5 = log20

x= [log20 ÷ log5]

[1.30103 ÷ 0.69897]

x = 1.861

1,125.

Make x the subject of the equation
s = 2 + \(\frac{t}{5} \)(x + ⅗y)

A.

x = 5[(s − 2) ÷ t] - 3/5y

B.

x = 25[(s − 2) ÷ t] − 3ty

C.

x = [1 ÷ (s − 2)3ty]

D.

x = [5(s − 2) 2 ÷ 3ty] × t

Correct answer is A

No explanation has been provided for this answer.