How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Find the next three terms of the sequence; 0, 1, 1, 2, 3, 5, 8...
13, 19, 23
9, 11, 13
11, 15, 19
13, 21, 34
Correct answer is D
No explanation has been provided for this answer.
The relation y = x2 + 2x + k passes through the point (2,0). Find the value of k
- 8
- 4
4
8
Correct answer is A
Y = x2 + 2x + k (given)
y = o when x = 2
thus 0 = 22 + 2 x 2 + k
0 = 4 + 4 + k
given k = -8
\(\frac{2}{9}\)
\(\frac{5}{18}\)
\(\frac{20}{81}\)
\(\frac{5}{9}\)
Correct answer is C
n(red balls) = 5
n(blue balls) = 4
n(\(\iff\)) = 9
Hence, prob (R1, B2)
= \(\frac{5}{9} \times \frac{4}{9}\)
= \(\frac{20}{81}\)
In the diagram, O is the centre of the circle, < QPS = 100o, < PSQ = 60o and < QSR. Calculate < SQR
20o
40o
60o
80o
Correct answer is A
In the diagram, < RPQ = 80o(angles in same segment)
< SPR = 100o - < RPQ
= 100 - 80
= 20o
< SQR = < SPR = 20o (same reason as above)
< SQR = 20o
Simplify \(\frac{(p - r)^2 - r^2}{2p^2 - 4pr}\)
\(\frac{1}{2}\)
p - 2r
\(\frac{1}{p - 2r}\)
\(\frac{2p}{p - 2r}\)
Correct answer is A
\(\frac{(p - r)^2 - r^2}{2p^2 - 4pr}\)
= \(\frac{(p - r)(p - r) - r^2}{2p^2 - 4pr}\)\
= \(\frac{p^2 - 2pr + r^2 - r^2}{2p(p - 2r}\)
= \(\frac{p^2 - 2pr}{2p(p - 2r)}\)
= \(\frac{p(p - 2r)}{2p(p - 2r)}\)
= \(\frac{1}{2}\)