How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
90\(^o\)
60\(^o\)
45\(^o\)
30\(^o\)
Correct answer is B
In the diagram, < WOZ = 180\(^o\) (angle on a straight line)
< WOX = < XOY = < YOZ
(|WX| = |XY| = |YZ|)
\(\frac{180^o}{3}\) = 60\(^o\)
= 60\(^o\)
M + m =2m (base angles of isosceles \(\bigtriangleup\), |OY| and |OZ| are radii)
< YOZ + 2m (base angles of a \(\bigtriangleup\))
60\(^o\) + 2m = 180\(^o\) (sum of a \(\bigtriangleup\))
60\(^o\) + 2m = 180\(^o\)
2m = 180\(^o\) - 60\(^o\)
2m = 120\(^o\)
m = \(\frac{120^o}{2}\)
= 60\(^o\)
The solution of x + 2 \(\geq\) 2x + 1 is illustrated
i
ii
iii
iv
Correct answer is A
x + 2 \(\geq\) 2x + 1
x - 2x \(\geq\) 1 - 2
-x \(\geq\) -1
\(\frac{-x}{-1}\) \(\geq\) \(\frac{-1}{-1}\)
x \(\leq\) 1
25cm\(^2\)
24cm\(^2\)
16cm\(^2\)
12cm\(^2\)
Correct answer is B
Area of shaded part = 2 x area of \(\bigtriangleup\)SPQ
= 2 x \(\frac{1}{2}\) 8 x 3 =24cm
Hence, area of the unshaded part of the rectangle = area of rectangle - area of shaded part
= 8 x 6 - 24
= 48 - 24
= 24 cm\(^2\)
110\(^o\)
135\(^o\)
165\(^o\)
225\(^o\)
Correct answer is C
In the diagram,
Thus, m = 2 x 55\(^o\) (is a bisector of obtuse
m = 110\(^o\)
n = \(\frac{1}{2}\) x 110\(^o\) (angle at centre = 2 x angle at circum)
n = 55\(^o\)
m + n = 110 + 55 = 165\(^o\)
Trapezium
Prism
Rectangle
Rhombus
Correct answer is D
No explanation has been provided for this answer.