How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
The graph of y = \(ax^2 + bx + c\) is shown oon the diagram. Find the minimum value of y
-2, 0
-2, 1
-2, 3
-2, 5
Correct answer is B
No explanation has been provided for this answer.
Find the value of m in the diagram
72\(^o\)
68\(^o\)
44\(^o\)
34\(^o\)
Correct answer is C
2x + m = 180
x + m = 112
x = 122 - m
2(112 - m) + m = 180
224 - 2m + m = 180
224 - m = 180
224 - 180 = m
m = 44\(^o\)
The diagonal of a square is 60 cm. Calculate its peremeter
20\(\sqrt{2}\)
40\(\sqrt{2}\)
90\(\sqrt{2}\)
120\(\sqrt{2}\)
Correct answer is D
\(60^2 + x^2 + x^2\)
\(360^2 = 2x^2\)
\(x^2\) = 1800
x = \(\sqrt{1800}\)
x = 42.4264
x = 42.4264
perimeter = 4x
= 4 x 42.4264
= 169.7056
= 120\(\sqrt{2}\)
= 120\(\sqrt{2}\)
36.87\(^o\)
39.70\(^o\)
51.34\(^o\)
53.13\(^o\)
Correct answer is C
Tan \(x^o = \frac{100m}{80}\)
Tan \(x^o = Tan^{-1} 1.25\)
x = 51.34\(^o\)
In the diagram, NQ//TS, <RTS = 50\(^o\) and <PRT = 100\(^o\). Find the value of <NPR
110\(^o\)
130\(^o\)
140\(^o\)
150\(^o\)
Correct answer is B
< TSR = 180 - (80 + 50)
= 180 - (130)
= 50\(^o\)
< QPR = < TSR corresponding < s
< NPR + QPR = < NPR
180\(^o\) - < QPR = < NPR
180\(^o\) - 50 = < NPR
< NPR = 130\(^o\)