Line Charts Questions & Answers - Page 7

31.

The following line graph gives the percentage of the number of candidates who qualified for an examination out of the total number of candidates who appeared for the examination over a period of seven years from 1994 to 2000.

Percentage of Candidates who Qualified to Appeared in an Examination Over the Years

If the total number of candidates who appeared in 1996 and 1997 together was 47400, then the total number of candidates who qualified in these two years together was?

A.

34700

B.

32100

C.

31500

D.

Data inadequate

Correct answer is D

The total number of candidates who qualified in 1996 and 1997 together, cannot be determined until we know at least, the number of candidates who appeared in any one of the two years 1996 or 1997 or the percentage of candidates who qualified to candidates who appeared in 1996 and 1997 together.

Hence, the data is inadequate.

32.

The following line graph gives the percentage of the number of candidates who qualified for an examination out of the total number of candidates who appeared for the examination over a period of seven years from 1994 to 2000.

Percentage of Candidates who Qualified to Appeared in an Examination Over the Years

If the number of candidates who qualified in 1998 was 21200, what was the number of candidates who appeared in 1998?

A.

32000

B.

28500

C.

26500

D.

25000

Correct answer is C

The number of candidates appeared in 1998 be x.

Then, 80% of x = 21200   =>   x = (21200 x 100)/80 = 26500 (required number)

33.

The following line graph gives the percentage of the number of candidates who qualified for an examination out of the total number of candidates who appeared for the examination over a period of seven years from 1994 to 2000.

Percentage of Candidates who Qualified to Appeared in an Examination Over the Years

In which pair of years was the number of candidates who qualified, the same?

A.

1995 and 1997

B.

1995 and 2000

C.

1998 and 1999

D.

Data inadequate

Correct answer is D

The graph gives the data for the percentage of candidates qualified to appeared and unless the absolute values of number of candidates qualified or candidates appeared is know we cannot compare the absolute values for any two years.

Hence, the data is inadequate to solve this question.

34.

The following line graph gives the percentage of the number of candidates who qualified for an examination out of the total number of candidates who appeared for the examination over a period of seven years from 1994 to 2000.

Percentage of Candidates who Qualified to Appeared in an Examination Over the Years

The difference between the percentage of candidates qualified and candidates who appeared was maximum in which of the following pair of years?

A.

1994 and 1995

B.

1997 and 1998

C.

1998 and 1999

D.

1999 and 2000

Correct answer is B

The differences between the percentages of candidates qualified to appeared for the give pairs of years are:

For 1994 and 1995 = 50 - 30 = 20.

For 1998 and 1999 = 80 - 80 = 0.

For 1994 and 1997 = 50 - 30 = 20.

For 1997 and 1998 = 80 - 50 = 30.

For 1999 and 2000 = 80 - 60 = 20.

Thus, the maximum difference is between the years 1997 and 1998.

35.

The following line graph gives the percent profit earned by two Companies X and Y during the period 1996 - 2001.

Percentage profit earned by Two Companies X and Y over the Given Years

%Profit = ((Income - Expenditure) / Expenditure) x 100

If the incomes of the two Companies were equal in 1999, then what was the ratio of expenditure of Company X to that of Company Y in 1999 ?

A.

6:5

B.

5:6

C.

11:6

D.

16:15

Correct answer is D

Let the incomes of each of the two Companies X and Y in 1999 be Rs. x.

And let the expenditures of Companies X and Y in 1999 be E1 and E2 respectively.

Then, for Company X we have:

50 = (x - E1)/E1 x 100 => 50/100 = (x/E1) - 1 => x = 150/100 E1 .... (i)

Also, for Company Y we have:

60 = (x - E2)/E2 x 100 => 60/100 = (x/E2) - 1 => x = 160/100 E2 .... (ii)

From (i) and (ii), we get:

150/100 E1 = 160/100 E2 => E1/E2 = 160/150 = 16/15 (Required ratio)