A battery of e.m.f 10V and internal resistance 2Ω is co...
A battery of e.m.f 10V and internal resistance 2Ω is connected to a resistance of 6Ω. Calculate the p.d
8.75V
7.50V
5V
2.50V
1.25V
Correct answer is B
V = E - Ir = 10V - \(\frac{10 \times 2}{8}\) = 7.5V
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