The coefficient of static friction between a 40kg crate and concrete surface is 0.25. Find the magnitude of the minimum force needed to keep the crate stationary on the concrete base inclined at 45° to the horizontal. [G = 10ms^-1]

400N

300N

283N

212N

Correct answer is D

momentum force = Rsin\(\theta\) - \(\mu\)Rcos\(\theta\)

Fm = (40 x 10 x sin 45) - (40 x 10 x 0.25 x cos 45)

= 212N

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The coefficient of static friction between a 40kg crate and concrete surface is 0.25. Find the magnitude of the minimum force needed to keep the crate stationary on the concrete base inclined at 45° to the horizontal. [G = 10ms-1]